Answer:42 cm 3 cubic unit
Explanation:
The efficiency of the machine is defined as

Here
Work out is the work output and Work in is the work input
To find the Work in we have then


Replacing with our values


The work done by the applied force is
W = Fd
Here,
F = Force
d = Distnace
Rearranging to find F,


F = 129.77N
Therefore the force exerted on the machine after rounding off to two significant figures is 130N
Answer:
y = 3.159 m
Explanation:
Using the second equation of motion.
s = ut + 0.5at^2 .......1
Since the ball is thrown upward the acceleration due to gravity act against it.
Given:
distance s = y
Initial speed u = 12.0 m/s
Time t = 0.30 s
Acceleration a = -g = -9.8m/s^2
Equation 1 becomes;
y = ut - 0.5at^2
Substituting the given values. We have;
y = 12.0(0.30) - 0.5(9.8 × 0.3^2)
y = 3.6 - 0.441
y = 3.159 m
Answer:
<em> The current decreases.</em>
Explanation: