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Sergio [31]
3 years ago
7

Can someone help me in the 26th one pleaseeee​

Physics
1 answer:
Elodia [21]3 years ago
4 0
Yes I can help jus tell me what the 26th question is
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7 0
3 years ago
As a glacier melts, the volume V of the ice, measured in cubic kilometers, decreases at a rate modeled by the differential equat
DaniilM [7]

Answer:

the volume in terms of time t ⇒ \\V = e^{0.05t} + 399\\

Explanation:

Given that :

\frac{dv}{dt}= kv\\\\\int\limits \, \frac{dv}{v}=  \int\limits \, kdt\\In v = kt + C_1\\v = e^{kt} + C\\400 = e^{k*0} + C\\400 = 1 + C\\C = 400 -1\\C = 399

V = e^{kt} + 399

When v = 300 ;  \frac{dv}{dt}= - 15

then

\frac{dv}{dt}= kv\\\\-15 = 300*k\\\\k = \frac{-15}{300}\\\\\\k = \frac{-1}{20}\\\\k = -0.05

∴ \\V = e^{0.05t} + 399\\

Therefore, the volume in terms of time t ⇒ \\V = e^{0.05t} + 399\\

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3 years ago
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The answer is the last choice.

Its electrical potential energy stays the same because it has the same electric potential. The reason why is that moving the charge towards X does not change the distance of the negative charge between the plates. The Electrical potential energy of a particle is the result energy by virtue of its position from the electrical fields produce by the plates both positive and negative. Since the charge is still equidistant to each other (assuming based from the diagram) no change in terms of electrical energy consumption or work was done.
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3 years ago
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