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Sergio [31]
4 years ago
7

Can someone help me in the 26th one pleaseeee​

Physics
1 answer:
Elodia [21]4 years ago
4 0
Yes I can help jus tell me what the 26th question is
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Consider an old-fashion bicycle with a small wheel of radius 0.17 m and a large wheel of radius 0.92 m. Suppose the rider starts
Gala2k [10]

Answer:

10259.6 m

Explanation:

We are given that

Radius of small wheel,r=0.17 m

Radius of large wheel,r'=0.92 m

Initial velocity,u=0

Time,t=2.7 minutes=162 s

1 min=60 s

Velocity,v=10m/s

Time,t'=13.7 minutes=822 s

Time,t''=4.1 minutes=246 s

v=u+at

Substitute the values

10=0+162a=162a

a=\frac{10}{162}=0.0617m/s^2

s=ut+\frac{1}{2}at^2

Substitute the values

s=\frac{1}{2}(0.0617)(162)^2=809.6 m

s'=vt'=10\times 822=8220 m

a'=\frac{v}{t''}=\frac{10}{246}

s''=\frac{1}{2}a't''^2=\frac{1}{2}\times \frac{10}{246}(246)^2=1230 m

Total distance traveled by rider=s+s'+s''=809.6+8220+1230=10259.6 m

6 0
4 years ago
Read 2 more answers
Kamir and Alexis are studying the properties of water. They conducted a variety of experiments to determine its physical and che
solniwko [45]

The answer is D) neutral water reacts with carbon dioxide to form an acid solution

4 0
3 years ago
Read 2 more answers
Answers are - <br><br>A 235 N<br><br>B 376 N<br><br>C 271 N<br><br>D 188 N<br><br>E 470 N
amm1812

Answer:

C

Explanation:

8 0
3 years ago
Masses A and B rest on very light pistons that enclose a fluid.There is no friction between the pistons and the cylinders they f
RSB [31]

Answer:

D)Not enough information

Explanation:

According to Pascal's principle, the pressure exerted on the two pistons is equal:

p_A = p_B

Pressure is given by the ratio between force F and area A, so we can write

\frac{F_A}{A_A}=\frac{F_B}{A_B}

The force exerted on each piston is just equal to the weight of the corresponding mass: F=W=mg, where m is the mass and g is the gravitational acceleration. So the equation becomes

\frac{m_A g}{A_A}=\frac{m_B g}{A_B}

Now we can rewrite the mass as the product of volume, V, times density, d:

\frac{V_A d_A g}{A_A}=\frac{V_B d_B g}{A_B}

We also know that A_B = 2.0 m^2\\A_A = 1.0 m^2

So we can further re-arrange the equation (and simplify g as well):

\frac{V_A d_A}{1}=\frac{V_B d_B}{2}

\frac{d_A}{d_B}=\frac{V_B}{2V_A}

We are also told that block B has bigger volume than block A: V_B > V_A. However, this information is not enough to allow us to say if the fraction on the right is greater than 1 or smaller than 1: therefore, we cannot conclude anything about the densities of the two objects.

3 0
3 years ago
If you were stuck in the center of the bridge when it was swaying, where would be the safest place to walk back to land?
Ludmilka [50]
Straight
You already have to momentum of walking forward, and going back and forth are the same distance. If you go back then you would have to stop, turn and walk, but if you go forward you just have to walk.
4 0
3 years ago
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