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tankabanditka [31]
1 year ago
9

4. If a 75 kg astronaut moves from Earth to Mars, how much weight did he lose?

Physics
1 answer:
zalisa [80]1 year ago
5 0
He doesn't lose weight he stays the same weight it's just gravity that changes
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A stone is thrown vertically upward with velocity 9.8ms 1)calculate the time taken to reach maximum height.2)what is the maximum
ira [324]

Answer:

1.t=-1.96sec

2.H=4.8m

3.T=1.96sec

4.R=19.2m

Explanation:

u=9.8,t=?,sin theta=1

using formula t=2usintheta/g

t=2x9.8x1=19.6/10

t=1.96seconds

using formula H=u(squared)sin(squared)theta/2g

H=9.8(squared)x1(squared)/2x10

H=96x1/20

H=96/20

H=4.8m

using formula T=2usintheta/g

T=2x9.8x1/10

T=19.6/10

T=1.96sec

using the formula R=u(squared)sin2theta/g

R=9.8(squared)x2/10

R=96x2/10

R=192.08/10

R=19.2

5 0
3 years ago
Read 2 more answers
An object has a velocity of 8 m/s and a kinetic energy of 480 J. What is the mass of the object? (Formula: )
Furkat [3]
KE = 1/2 * m * v2

We have to rearrange this so the subject is mass. (because the question asks for the mass of the object) :

Mass = (2 * KE) / v

Now input the values into this equation to get your answer :

Mass = (2 * KE) / v
Mass = (2 * 480) / 8
Mass = 960 / 8
Mass = 120
7 0
3 years ago
Read 2 more answers
HELP PLSSS
Andrews [41]

Given :

A 13.3 kg box sliding across the ground  decelerates at 2.42 m/s².

To Find :

The coefficient of kinetic friction.

Solution :

Frictional force applied to the box is :

f = ma    ....1)

Also, force of friction is given by :

f = \mu mg  ....2)

Equating equation 1) and 2), we get :

\mu mg = ma\\\\\mu = \dfrac{a}{g}\\\\\mu = \dfrac{2.42}{9.8}\\\\\mu = 0.247

Therefore, the coefficient of kinetic friction is 0.247 .

8 0
3 years ago
PLEASE HELP ME!!!! During ________ particles and/or radiation are emitted or given off.
Aliun [14]
C. Radioactive decay
5 0
3 years ago
A student climbs to the top of the gym and drops a baseball to the ground below. A physics student standing nearby has a motion
sladkih [1.3K]

Answer:

The baseball was falling during 1.733 seconds.

Explanation:

The baseball experimented a free fall, which is a particular case of uniformly accelerated motion, in which object is accelerated by gravity. In this case, we need to determine the time spent by the ball before hitting the ground (t), measured in seconds, which is determined by the following kinematic formula:

t = \frac{v-v_{o}}{g} (1)

Where:

v_{o}, v - Initial and final speeds of the baseball, measured in meters per second.

g - Gravitational acceleration, measured in meters per square second.

If we know that v_{o} = 0\,\frac{m}{s}, v = 17\,\frac{m}{s} and g = 9.807\,\frac{m}{s^{2}}, then the time spent by the baseball is:

t = \frac{17\,\frac{m}{s}-0\,\frac{m}{s}  }{9.807\,\frac{m}{s^{2}} }

t = 1.733\,s

The baseball was falling during 1.733 seconds.

6 0
3 years ago
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