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3 years ago

The sum of two consecutive integer is 131. Find the integer

2 answers:

7 0

$x,\ x+1-\text{two consecutive integer}\\\\\text{The equation}\\\\x+(x+1)=131\ \ \ \ \ |\text{use associative property}\\\\(x+x)+1=131\\\\2x+1=131\ \ \ \ \ |\text{subtract 1 from both sides}\\\\2x=130\ \ \ \ |\text{divide both sides by 2}\\\\x=65\\\\x+1=65+1=66$

<h3>Answer: 65 and 66</h3>

AlexFokin [52]3 years ago

3 0

$n+n+1=131\\\\2n=130\\\\n=65\\\\n+1=66$

<u>65 and 66</u>

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Which shows the correct substitution of the values a, b, and c from the equation 0 = – 3x2 – 2x + 6 into the quadratic formula?

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An expression which shows the correct substitution of the values a, b, and c from the equation 0 = – 3x2 – 2x + 6 into the quadratic formula is: expression A. Therefore, the correct answer option is A.

<h3>What is a quadratic equation?</h3>

A quadratic equation can be defined as a mathematical expression (equation) that can be used to define and represent the relationship that exists between two or more variable on a graph. In Mathematics, the standard form of a quadratic equation is given by;

ax² + bx + c = 0

Mathematically, the quadratic formula is modeled or represented by this mathematical expression:

$x = \frac{-b\; \pm \;\sqrt{b^2 - 4ac}}{2a}$

From the information provided, we have the following values;

0 = -3x² - 2x + 6

Where:

a = -3

b = -2

c = 6

Substituting the values into the quadratic formula, we have;

$x = \frac{-(-2)\; \pm \;\sqrt{(-2)^2 - 4(-3)(6)}}{2(-3)}\\\\x = \frac{2\; \pm \;\sqrt{4^2 - 4(-3)(6)}}{2(-3)}$

Read more on quadratic equation here: brainly.com/question/4053652

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