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skelet666 [1.2K]
3 years ago
7

How many atoms are in 163 g of calcium?

Chemistry
2 answers:
I am Lyosha [343]3 years ago
8 0
<span>Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles.

163 g Ca (1 mol / 40.08 g) ( </span>6.022 x 10^23 atoms / 1 mol ) = 2.45 x10^24 atoms Ca
12345 [234]3 years ago
6 0

Answer: 24.5\times 10^{23}atoms

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar Mass}}=\frac{163g}{40g/mol}=4.075moles

1 mole of calcium contains = 6.023\times 10^{23}atoms

Thus 4.075 moles of calcium contains = \frac{6.023\times 10^{23}}{1}\times 4.075 =24.5\times 10^{23}atoms

Thus there are 24.5\times 10^{23}atoms in 163 g of calcium.

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3 years ago
Consider the following reaction at constant P. Use the information here to determine the value of ΔSsurr at 355 K. Predict whet
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The given reaction is as follows:

2NO (g) + O₂ (g) = 2NO₂ (g), ΔH = -114 kJ

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Hence, the value of dSsurr is +321.12 J/K

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Also dStotal = dSsys + dSsurr > 0

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8 0
3 years ago
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