Explanation:
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Answer:
m = 29.6 grams
Explanation:
Given that,
Number of moles = 0.540
The molar mass of manganese = 54.93 g/mol
We know that,
Number of moles = given mass/molar mass
So, the required mass of the Manganese is equal to 29.6 grams.
Answer:
Explanation:
Use Avogadro’s number to convert formula units of RbNO₃ to moles of RbNO₃.
1 mol RbNO₃ ≡ 6.022 × 10²³ formula units RbNO₃
Moles of RbNO₃ = 2.41 ×1 0²⁴ × = 4.00 mol RbNO₃
There are of RbNO₃ in 2.41 × 10²⁴ formula units.