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Lilit [14]
3 years ago
13

AlCl3 and NaNO3 Balanced Equation Total Ionic Equation Net Ionic Equation

Chemistry
1 answer:
o-na [289]3 years ago
6 0

Answer:

a) <u>Balanced Equation</u>

Al(NO₃)₃ + 3NaCl   →   AlCl₃ + 3NaNO₃

b) <u>Total Ionic Equation</u>

Al³⁺ + 3NO₃⁻ + 3Na⁺ + 3Cl⁻   →   Al³⁺ + 3Cl⁻ + 3Na⁺ + 3NO₃⁻

c) <u>Net Ionic Equation</u>: None

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Partner Namets) For each of the following reactions carried out: Write the balanced chemical equation, the full ionic equation,
torisob [31]

Answer : The full balanced ionic equation will be,

2KI(aq)+Pb(NO_3)_2(aq)\rightarrow 2KNO_3(aq)+PbI_2(s)

Reactants are lead nitrate and potassium iodide.

Products are lead iodide and potassium nitrate.

The spectator ions are, K^+,NO_3^-

Explanation :

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

When potassium iodide react with lead nitrate then it gives potassium nitrate and lead iodide as a product.

The full balanced ionic equation will be,

2KI(aq)+Pb(NO_3)_2(aq)\rightarrow 2KNO_3(aq)+PbI_2(s)

The ionic equation in separated aqueous solution will be,

2K^+(aq)+2I^{-}(aq)+Pb^{2+}(aq)+2NO_3^{-}(aq)\rightarrow PbI_2(s)+2K^+(aq)+2NO_3^{-}(aq)

In this equation, K^+\text{ and }NO_3^- are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

Pb^{2+}(aq)+2I^{-}(aq)\rightarrow PbI_2(s)

4 0
3 years ago
A nitrogen atom has five valence electrons. The Lewis structure shows how a nitrogen atom bonds with three hydrogen atoms to for
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It has too be 6 or 4

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Answer:

Whats the hypothesis and the experiment?

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I believe you mean what amount  of O2 contains 1.8 x 10^22 molecules. 

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02989 moles. Rounded to the nearest hundredths,.<span>0299</span>
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