Answer:
In models describing the structure of the plant cell wall, the polysaccharide cellulose,which only contains glucose,forms cable-like structures which are associated with interspersed hemicellulose polysaccharides which consist of glucose chains with xylose side groups. The pectin polysaccharides, containing ironic acids, have a more kinked ribbon-like structure and serve to link the cellulose polysaccharides together by providing a gel-like matrix,completing the cell wall structure.
Explanation:
In the titration of lemon juice, the presence of ascorbic acid means the concentration of citric acid you calculated is higher.
An acid-base titration is a common way to determine the unknown concentration of an acid, given we know the concentration of the base and determine the spent volume in the titration. Let's consider the neutralization reactions that take place in a mixture of citric acid and ascorbic acid.
Citric acid titration :
3 NaOH(aq) + H₃C₆H₅O₇(aq) → Na₃C₆H₅O₇(aq) + 3 H₂O(l)
Ascorbic acid titration:
NaOH(aq) + HC₆H₇O₆(aq) → NaC₆H₇O₆(aq) + H₂O(l)
If we titrated a solution that contained only citric acid, we can relate through stoichiometry the moles and concentration of citric acid. However, if the solution also contained ascorbic acid, we would have to spend more NaOH to titrate it. Since more NaOH would react, we would conclude that there is more citric acid to react, calculating a higher concentration of the same.
In the titration of lemon juice, the presence of ascorbic acid means the concentration of citric acid you calculated is higher.
You can learn more about titration here: brainly.com/question/2728613
We are given with the reaction HCOOH(g) →CO2(g) + H2 (g). According to Dalton's law, the total pressure of a vessel is equal to the sum of the partial pressure of the components inside it. In this case, we plot first the data ln (ratio partial pressure of HCOOH to total pressure) vs time. Partial pressure is the difference of pressure (from one point to another). In this case, the equation is ln P(HCCOH) = -0.0146t - 0.2281 where R² = 0.9923. K is equal to <span> -0.0146 s-1. When the total pressure is 291, ln P is -0.66938, thus the time is 30.23 seconds. The half life is ln(0.5)/k equal to 47.46 seconds.</span>
Answer: Basilosaurus is a prehistoric whale which lived approximately 40 million to 34 million years ago during the Late Eocene Period.
Explanation:
<span>a. 0.325 g / 63.55 g/mol = 5.11 X 10^-3 moles Cu. SHould form 5.11 X 10^-3 mol Cu2+
b. Should form 5.11 X 10^-3 mol Cu(OH)2
c. 1 g Zn / 65.4 g/mol = 0.0153 mol Zn
Excess Zn = 0.0153 - 0.0051 = 0.0102 moles excess zinc
d. 5.11 X 10^-3 mol Mg X 24.3 g/mol = 0.124 grams Mg</span>
