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Fofino [41]
3 years ago
9

Can somebody help me with this please

Chemistry
1 answer:
denpristay [2]3 years ago
3 0

Answer:

He, 2, 2, 2, 4, 4-2=2, 1, 8

I, 53, 53, 53, 127, 127-53= 74, 5, 7

Explanation:

um check the periodic table for the rest?

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PH of 0,035M HCl? How to count if your calculator hasn't got -lg?
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<u>Given information:</u>

Concentration of HCl = 0.035 M

<u>To determine:</u>

pH of the solution

<u>Explanation:</u>

Hydrochloric acid, HCl is a strong acid. It will completely dissociate to give H+ and Cl- ions

HCl → H+ + Cl-

Hence the concentration of H+ = Cl- = 0.035M

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The gas in a cylinder has a volume of 7 liters at a pressure of 107kPa. The pressure of the gas is increased to 208kPa. Assuming
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If 10.00 g of iron metal is burned in the presence of excess of O2 how many grams of Fe2O3 will form
sergiy2304 [10]

14.292 grams of Fe2O3 is formed when 10 gram of iron metal is burned.

Explanation:

The balanced equation for the reaction is to be known so that number of moles taking part can be known.

The balanced chemical equation is

4Fe + 3O_{2}⇒ 2 Fe{2}O{3}

From the given weight of iron to be used for the production of Fe{2}O{3}, number of moles of Fe taking part in the reaction can be known by the formula:

Number of moles= mass ÷ Atomic mass of one mole of the element.

(Atomic weight of Fe is 55.845 gm/mole)

  Putting the values in equation  

Number of moles =  10 gm  ÷ 55.845 gm/mole

                               =  0.179 moles

Applying the stoichiometry concept

4 moles of Fe gives 2 Moles of Fe2O3

0.179 moles will produce x moles of Fe2O3

 So,  2÷ 4 = x ÷ 0.179

     2/4 = x/ 0.179

    2 × 0.179 = 4x

     2 × 0.179 / 4 = x

  x = 0.0895 moles

So from 10 grams of iron metal 0.0895 moles of Fe2O3 is formed.

Now the formula used above will give the weight of Fe2O3

weight = atomic weight × number of moles

            =  159.69 grams ×  0.0895

             = 14.292 grams of Fe2O3 formed.

4 0
3 years ago
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