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Vadim26 [7]
3 years ago
10

What is chemical reaction?​

Chemistry
2 answers:
Anon25 [30]3 years ago
5 0
A chemical reaction is a process where one or more substances or reactants are converted to one or more different substances or products. a chemical reaction rearranges the constituent atoms of the reactants to create different products
Aliun [14]3 years ago
3 0

Answer:

a process that involves rearrangement of the molecular or ionic structure of a substance, as distinct from a change in physical form or a nuclear reaction

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2MG+O2 ...........2MGO
Galina-37 [17]
Mg + 1/2 O2 → MgO

1 mol = 24 g of Mg

X mol = 12 g of Mg

x = 0.5 moles of Mg

Mg :MgO = 1:1 (coefficient from equations using mole ratio)

So

0.5 moles of MgO

1 mol MgO = (24+16) g = 40 g

0.5 moles of MgO = 0.5 × 40

= 20 g of MgO produced
5 0
3 years ago
Helium is an odorless, colorless gas at room temperature. It is less dense than air. That's why helium balloons float. It is a n
Zolol [24]

Answer:

  • Non-flammable
  • It is the only element that doesn't solidify under ordinary pressure and remains a liquid enven at absolute zero.
  • When it electricity runs through helium it glows a pale peach color.
5 0
3 years ago
Suppose you have 15.0 ml of zinc. What volume of aluminum would have the same mass as the zinc?
Black_prince [1.1K]

Answer:

\large \boxed{\text{41.2 cm}^{3}}

Explanation:

1. Mass of zinc

The density of zinc is 7.14 g/cm³

D = m/V

\begin{array}{rcl}7.14 & = & \dfrac{m}{15.0}\\\\m & = & 7.14 \times 15.0\\& = & \text{107.1 g}\\\end{array}\\

2. Volume of aluminium

The density of aluminium is 2.60/cm³.

\begin{array}{rcl}2.60 & = & \dfrac{107.1}{V}\\\\2.60V & = & 107.1\\V& = &\dfrac{107.1}{2.60}\\\\& = &\textbf{41.2cm}^{\mathbf{3}}\\\end{array}\\\large \boxed{\textbf{41.2 cm}^{\mathbf{3}}}\text{ of aluminium have the same mass as 15.0 cm$^{3}$ of zinc.}

5 0
4 years ago
Convert 1.71 × 1024 atoms of carbon to moles of carbon.
beks73 [17]
You need to use Avogadro's constant to convert from atoms of carbon to moles of carbon.

1.71*10^24 atoms C * (1 mole/6.022*10^23 atoms) = 2.84 moles of carbon
7 0
3 years ago
A buffer is prepared containing 0.75 M NH3 and 0.20 M NH4 . Calculate the pH of the buffer using the Kb for NH3. g
denis-greek [22]

Answer:

pH=8.676

Explanation:

Given:

0.75 M NH_{3}

0.20 M NH_{4}

The objective is to calculate the pH of the buffer using the kb for NH_3

Formula used:

pOH=pka+log\frac{[salt]}{[base]}\\

pH=14-pOH

Solution:

On substituting salt=0.75 and base=0.20 in the formula

pOH=-log(1.77*10^{-5})+log\frac{0.75}{0.20}\\        =4.75+0.5740\\        =5.324

pH=14-pOH

On substituting the pOH value in the above expression,

pH=14-5.324

Therefore,

pH=8.676

3 0
3 years ago
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