Mg + 1/2 O2 → MgO
1 mol = 24 g of Mg
X mol = 12 g of Mg
x = 0.5 moles of Mg
Mg :MgO = 1:1 (coefficient from equations using mole ratio)
So
0.5 moles of MgO
1 mol MgO = (24+16) g = 40 g
0.5 moles of MgO = 0.5 × 40
= 20 g of MgO produced
Answer:

Explanation:
1. Mass of zinc
The density of zinc is 7.14 g/cm³
D = m/V

2. Volume of aluminium
The density of aluminium is 2.60/cm³.

You need to use Avogadro's constant to convert from atoms of carbon to moles of carbon.
1.71*10^24 atoms C * (1 mole/6.022*10^23 atoms) = 2.84 moles of carbon
Answer:
pH=8.676
Explanation:
Given:
0.75 M 
0.20 M 
The objective is to calculate the pH of the buffer using the kb for 
Formula used:
![pOH=pka+log\frac{[salt]}{[base]}\\](https://tex.z-dn.net/?f=pOH%3Dpka%2Blog%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bbase%5D%7D%5C%5C)
pH=14-pOH
Solution:
On substituting salt=0.75 and base=0.20 in the formula

pH=14-pOH
On substituting the pOH value in the above expression,
pH=14-5.324
Therefore,
pH=8.676