The net cell reaction is given as 3 Ni²⁺ (aq) + 2 Cr (s) = 2 Cr³⁺ (aq) + 3 Ni (s), and the cell potential is 0.49 V.
<h3>What is a half-cell reaction?</h3>
A half cell reaction is given as the oxidation or the reduction reaction that takes place at each of the anode or the cathode, forming the net redox reaction.
The cell potential and the half-reactions are:
Ni²⁺ + 2e⁻ = Ni (s) E° = -0.25 V
Cr³⁺ + 3e⁻ = Cr (s) E° = -0.74 V
The anodic reaction is given as:
Cr (s) = Cr³⁺ + 3e⁻ E° = 0.74 V
The cathodic reaction is given as:
Ni²⁺ + 2e⁻ = Ni (s) E° = -0.25 V
Thus, the net reaction of the cell will be:
3 Ni²⁺ (aq) + 2 Cr (s) = 2 Cr³⁺ (aq) + 3 Ni (s)
The cell potential can be calculated as:
E° = E (cathode) + E (anode)
E° = 0.74 + (-0.25) V
E° = 0.49 V
Thus, the net cell reaction is given as 3 Ni²⁺ (aq) + 2 Cr (s) = 2 Cr³⁺ (aq) + 3 Ni (s), and the cell potential is 0.49 V.
Learn more about cell potential, here:
brainly.com/question/1313684
#SPJ4
