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3 years ago

What is the law of multiple proportions?

Chemistry

1 answer:

quester [9]3 years ago

6 0

Answer:

I think

(d) All compounds contain the same elements in the same properties

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why does a properly adjusted head restraint help prevent head and neck injuries to occupants in rear end collision?

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If it's properly adjusted ur head and nexk will stay in place for no further injuries.It helps so it don't move

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2 years ago

Read 2 more answers

Describe what happens as ice changes to water.

morpeh [17]

Answer:

The energy of the particles increase and the molecules move more quickly.

Explanation:

The molecules are moving from a solid (barely moves, molecules close together) to a liquid (molecules slide past each other and take any shape), so molecules are moving more and have more energy

8 0

2 years ago

Gaseous butano (CH,(CH),CH) will react with gaseous oxygen (0) to produce gaseous carbon dioxide (CO2) and goseous woter (11,0).

slega [8]

Answer:

Firstly, We have to convert it in the Miles formula...

No. of moles = Mass given/Molar Mass

So, the final answer be come

<h3> Ans - 50.8 gm and there same % is 50.8% butane in reaction </h3>

5 0

2 years ago

Which of the following has the greatest mass?

Annette [7]

Answer:

I guess one mole. of mercury

Explanation:

because mercury is denser

8 0

2 years ago

The reaction of ethane gas (C2H6) with chlorine gas produces C2H5Cl as its main product (along with HCl). In addition, the react

Kazeer [188]

Answer:

The percent yield of chloro-ethane in the reaction is 82.98%.

Explanation:

$C_2H_6+Cl_2\rightarrow C_2H_5Cl+HCl$

Moles of ethane = $\frac{300.0 g}{30 g/mol}=10 mol$

Moles of chlorine gases = $\frac{650.0 g}{71 .0 g/mol}=9.1549 mol$

As we can see that 1 mol of ethane react with 1 mole of chlorine gas.the 10 moles will require 10 mole of chlorine gas, but only 9.1549 moles of chlorine gas is present.

This means that chlorine gas is in limiting amount and amount of formation of chloro-ethane will depend upon amount of chlorine gas.

According to reaction , 1 mol of chloro ethane gives 1 mol of chloro-ethane.

Then 9.1549 moles of chlorien gas will give:

$\frac{1}{1}\times 9.1549 mol=9.1549 mol$ of chloro-ethane

Mass of 9.1549 moles of chloro-ethane:

9.1549 mol × 64.5 g/mol = 590.4910 g

Theoretical yield of chloro-ethane: 590.4910 g

Given experimental yield of chloro-ethane: 490.0 g

$\% Yield=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

$\%Yield (C_2H_5Cl)=\frac{490.0 g}{590.4910 g}\times 100=82.98\%$

The percent yield of chloro-ethane in the reaction is 82.98%.

6 0

2 years ago