Answer:
S(s) + O2(g) --> SO2(g)
Upper S (s) plus upper O subscript 2 (g) right arrow with delta above upper S upper O subscript 2 (g).
Explanation:
The reaction is given as;
Sulfur + oxygen --> Sulphur dioxide
Sulphur = S
Oxygen = O2
Sulfur dioxide = SO2
So we have;
S(s) + O2(g) --> SO2(g)
The crrect option is option A. Upper S (s) plus upper O subscript 2 (g) right arrow with delta above upper S upper O subscript 2 (g).
I think you can only have 3 water molecules because you need 2 hydrogen molecules in every water molecule and you have 6 hydrogen molecules so 6/2=3 and the reactant that is limited would be hydrogen since it limits the amount of water molecules you can have
2NaBr + Ca(OH)2 ➡️ CaBr2 + 2NaOH
Methane (CH4) = 1 carbon atom, 4 hydrogen
Sulphuric Acid (H2SO4) = 2 hydrogen atoms, 1 sulfur and 4 oxygen.
