Answer:
2Na⁺ (aq) and 2OH⁻(aq)
Explanation:
Spectator ions:
Spectator ions are those ions which are same on both side of chemical reaction. These ions are same in the reactant side and product side. Their presence can not effect the chemical equilibrium that's why when we write the net ionic equation these ions are neglect or omitted.
Given ionic equation:
Ba⁺²(aq) + 2OH⁻(aq) + 2Na⁺ (aq) + CO²⁻₃(aq) → BaCO₃(s) + + 2Na⁺ (aq) + 2OH⁻(aq)
In given ionic equation by omitting the spectator ions i.e, 2Na⁺ (aq) and 2OH⁻(aq) net ionic equation can be written as,
Net ionic equation:
Ba⁺²(aq) + CO²⁻₃(aq) → BaCO₃(s)
24 molecules of H2O are needed by the plant to produce 4 molecules of sugar.
<h2>What is
photosynthesis?</h2>
The process by which plants convert carbon dioxide, water, and sunlight into oxygen and sugar-based energy is known as photosynthesis.
<h3>The photosynthesis equation is as follows:</h3>
6CO2 + 6H2O + Sunlight → C6H12O6 + 6O2
The following three significant activities are involved in photosynthesis:
1. Chlorophyll absorbs light energy.
2. Water molecules are divided into hydrogen and oxygen and light energy is converted to chemical energy.
3. Carbon dioxide is converted to sugars.
Therefore, a plant needs four molecules of H2O and four molecules of CO2 to make one molecule of glucose or sugar, hence a plant needs 24 molecules of H2O and 24 molecules of CO2 to make four molecules of sugar.
Learn more about photosynthesis here:
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Answer:
See explanation
Explanation:
Coal is primarily used for electricity generation. The burning of coal leads to emission of gases such as oxides of carbon, oxides of sulphur, oxides of nitrogen and water vapour. All these go straight into the atmosphere.
Petroleum is primarily used as transportation fuels. The burning of petroleum oils mostly leads to the emission of oxides of carbon and sulphur together with water vapour into the atmosphere.
Answer:
B
Explanation:
The electrochemical series can be used to check if a particular element has a greater activity than the other. Firstly, on the electrochemical series, it can be seen that lead is at a higher position compared to mercury. All things being equal, it will show a higher activity than mercury and hence can knock it off its salt.
Although it is the Overall standard electrode potential that tells us if a reaction is feasible or not, we can use the activity series to quickly discern if the reaction is possible or not. The overall standard electrode potential of both is positive which makes the reaction to be feasible and hence lead can display mercury off its salt