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patriot [66]
3 years ago
8

Differences between looping and simersaulting​

Physics
1 answer:
Anika [276]3 years ago
3 0
Somersaulting- for longer distances.It bends the narrow end in the direction it wants to go & takes grip with tentacles. It releases the broad end and straightens up. like this it continues. looping- for shorter distances.


Hope this helps
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A 18.0-kg rock is sliding on a rough, horizontal surface at 7.10 m/s and eventually stops due to friction. the coefficient of ki
Bond [772]
A = .3*g = 2.94 m/s² 

<span>t = v/a = 9/2.94 = 3.061 sec </span>

<span>W = E/t = ½mv²/t = ½*40*9²/3.061 = 529.2 watts</span>
4 0
3 years ago
What is the mass of a 735-N weight on Earth?
Allisa [31]
W = mg,      Assuming g ≈ 9.8 m/s² on the earth surface.

735 N =  m* 9.8

735/9.8 =  m

75 = m

Mass , m = 75 kg.  B.
3 0
3 years ago
An ordinary flashlight battery has a potential difference of 1.2 V between its positive and negative terminals. How much work mu
Maru [420]

The work done to transport an electron from the positive to the negative terminal is 1.92×10⁻¹⁹ J.

Given:

Potential difference, V = 1.2 V

Charge on an electron, e = 1.6 × 10⁻¹⁹ C

Calculation:

We know that the work done to transport an electron from the positive to the negative terminal is given as:

W.D = (Charge on electron)×(Potential difference)

       = e × V

       = (1.6 × 10⁻¹⁹ C)×(1.2 V)

       = 1.92 × 10⁻¹⁹ J

Therefore, the work done in bringing the charge from the positive terminal to the negative terminal is 1.92 × 10⁻¹⁹ J.

Learn more about work done on a charge here:

<u>brainly.com/question/13946889</u>

#SPJ4

4 0
2 years ago
A car accelerates uniformly from rest to a speed of 6.6 m/s in 6.5 s. Find the acceleration the car presents during this time?
Art [367]

Answer:

1.02 m/s²

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 0 m/s

Final velocity (v) = 6.6 m/s

Time (t) = 6.5 s

Acceleration (a) =.?

Acceleration can simply be defined as the change of velocity with time. Mathematically, it can be expressed as:

a = (v – u) / t

Where:

a is the acceleration.

v is the final velocity.

u is the initial velocity.

t is the time.

With the above formula, we can obtain the acceleration of the car as follow:

Initial velocity (u) = 0 m/s

Final velocity (v) = 6.6 m/s

Time (t) = 6.5 s

Acceleration (a) =.?

a = (v – u) / t

a = (6.6 – 0) / 6.5

a = 6.6 / 6.5

a = 1.02 m/s²

Therefore, the acceleration of the car is 1.02 m/s²

3 0
3 years ago
A tank with a flat bottom is filled with water to a height of 4 meters. What is the pressure at any point at the bottom of the t
Mariulka [41]

<u>Answer</u>

C.39.2 kPa


<u>Explanation</u>

The pressure in liquids depend on the depth or what we call the liquid column(h), the density of the liquid(σ) and the the acceleration due to gravity(g).

h = 4.00 m

σ = 1000 Kg/m³

g = 9.8m/s²


Pressure Is given by;

P = σgh

= 1000 × 9.8 × 4

= 39200 Pa

=39.2 KPa

8 0
3 years ago
Read 2 more answers
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