Answer:
The answer is 1.87nm/s.
Explanation:
The
water loss must be replaced by
of sap. 110g of sap corresponds to a volume of

thus rate of sap replacement is

The volume of sap in the vessel of length
is
,
where
is the cross sectional area of the vessel.
For 2000 such vessels, the volume is

taking the derivative of both sides we get:

on the left-hand-side
is the velocity
of the sap, and on right-hand-side
; therefore,

and since the cross-sectional area is
;
therefore,

solving for
we get:


which is the upward speed of the sap in each vessel.
Work= force*distance
Work= x*12
Force= mass*acceleration
Force= 5 kg*6
Force= 40 N
Work= 40×12
Work= 480 J (joules)
I think this is it
Answer:
3125 N
Explanation:
diameter /2 =radius
so r1 =14cm , r2 =35cm
f1/A1 =f2/A2.
f2 = f1 × A2 / A1
=500×1225 pi cm² / 96 pi cm²
f2 =3125N
As one moves farther and farther from the Sun, the distance between adjacent planets is greater.