An air bubble underwater has the same pressure as that of the surrounding water. As the air bubble rises toward the surface (and
1 answer:
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Answer:
Option c) are perpendicular to the electric field
Explanation:
Equipotential surfaces are perpendicular to the electric field. the electric field lines are projected outwards from the equipotential surface, i.e., the lines of the electric field are at 90 to the equipotential surface.
Equipotential surface are those surfaces that have the same potential at any point on the surface. Thus the potential difference at any point on the surface is zero due to same potential.
Any charge particle on this surface will move in a perpendicular direction to the Coulombian force. No work is done by the force on a particle moving on an equipotential surface.
Answer:
- Bigger mass of planet B
- orbiting closer to planet B
Explanation:
The orbital velocity of the vessel around the planet can be found by equalizing the force of gravity between the vessel and the planet and the centripetal force:
where
G is the gravitational constant
m is the mass of the vessel
M is the mass of the planet
r is the distance between the vessel and the centre of the planet
v is the orbital velocity of the vessel
Re-arranging the formula, we find an expression for v:
We see that:
- the bigger the mass of the planet, M, the bigger the velocity
- the bigger the distance between the vessel and the planet, r, the smaller the velocity
So, the correct choices that increase the orbital velocity are:
- Bigger mass of planet B
- orbiting closer to planet B