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Zinaida [17]
4 years ago
14

In an emergency, a driver brings a car to a full stop in 5.0s. The car is traveling at a rate of 38m/s when the breaking begins.

Physics
1 answer:
Lana71 [14]4 years ago
6 0

(a) By definition of average acceleration,

<em>a</em> = ∆<em>v</em> / ∆<em>t</em> = (0 - 38 m/s) / (5.0 s)

<em>a</em> = -7.6 m/s²

(b) Recall that

<em>v</em>² - <em>u</em>² = 2 <em>a</em> ∆<em>x</em>

where <em>u</em> and <em>v</em> are initial and final velocities, respectively; <em>a</em> is acceleration; and ∆<em>x</em> is the change in position. So

0² - (38 m/s)² = 2 (-7.6 m/s²) ∆<em>x</em>

∆<em>x</em> = 95 m

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A 2,200-kg pile driver is used to drive a steel I-beam into the ground. The pile driver falls 3.40 m before coming into contact
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The magnitude of Force is 8.58×10⁵N and direction is upwards

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W_{nc}=(KE_{f}-KE_{i})+(PE_{f}-PE_{i})\\W_{nc}=1/2m(vf^{2}-vi^{2})+mg(yf-yi)

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