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vampirchik [111]

3 years ago

13

ILL GIVE BRAINLIEST. plsss help asap

1 answer:

arsen [322]3 years ago

8 0

Answer:

The answer to your question is A

Explanation:

because of Newton's second law of motion

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Bobo, the clown, can swim at 2.0 m/s. he must make a landing directly across to the north side of the styx river, which is 100.

victus00 [196]

We are given the following:

Bobo's swimming speed = 2.0 m/s
Width of the river = 100 m
Flowrate of the river = 6.0 m/s due east

First, we need to illustrate the problem. Draw the river with a width of 100 meters. Then, the flow of the river, east at 6 meters per second. Lastly, draw Bobo at one side of the river facing north and an arrow representing swimming speed at 2 meters per second.

Now, we can use the Pythagorean theorem to solve this rate problem.

c^2 = a^2 + b^2

c = speed of Bobo needed
a = speed of Bobo facing north
b = flow rate of the river going east

c^2 = 2^2 + 6^2

c = 6.32 m / s should be his speed to overcome the current and make a landing at the desired location.

6 0

4 years ago

A white billiard ball with mass mw = 1.37 kg is moving directly to the right with a speed of v = 3.14 m/s and collides elastical

Ira Lisetskai [31]

That latest value for the Angle is in Grads, not in Kilograms.

Apply law of conservation of momentum along vertical direction.

$m_1v_1sin\theta_1-m_2v_2sin\theta_2=0$

$v_2=\frac{v_1sin\theta_1}{sin\theta_2}=\frac{sin54}{sin36}v_1 = 1.376v_1$

Apply law of conservation of momentum along the horizontal direction

$m_1u_1=m_1v_1cos\theta_1+m_2v_2cos\theta_2$

$u_1=v_1(cos\theta_1+1.376cos\theta_2)$

$u_1=v_1(cos(54)+1.376cos(36))$

$u_1=(1.7) v_1$

$v_1= \frac{3.14}{1.7}=1.84m/s$

The second ball velocity is $v_2 = (1.376)(1.84)=2.531m/s$

The magnitud of final total momentum is

$m(v_1+v_2)=(1.37)(2.531+1.84)=5.98kgm/s$

The magnitude of final energy is

$\frac{1}{2}m(v^2_1+v^2_2)=\frac{1}{2}(1.37)(2.531^2+1.84^2)=6.07J$

6 0

3 years ago

Kelli drew a diagram to compare cast and imprint fossils. Which label belongs in the area marked Y? Involves minerals replacing

STatiana [176]

Answer:

the answer is c

Explanation:

an imprint gives evidence of an organisms activity they don't normally fill with sediments

8 0

2 years ago

Read 2 more answers

Compare the temperature of water before it is boiling and after it has boiled

damaskus [11]

Before it is boiled is <100 degrees Celsius and after it is boiled it would be > 100 degrees Celsius

8 0

4 years ago

Read 2 more answers

A hawk flying at 13 m/s at an altitude of 156 m accidentally drops its prey. The parabolic trajectory of the falling prey is des

Anvisha [2.4K]

Answer:

The distance traveled will be 156.0 m

Explanation:

Please, see the attached figure 1 for a description of the problem.

The distance traveled by the prey is the magnitude of the vector "r" (see figure).

If the components of "r" are "rx" (horizontal component) and "ry" (vertical component), its magnitude will be:

$|r| =\sqrt{(rx)^{2} + (ry)^{2}}$

We already know the vertical component of r, ry, because the prey falls from an altitude of 156 m (see figure). Then ry = 156 m

To find the value of rx we will use the function that describes the trajectory of the prey (see figure 2):

y = -39 · x² + 156

When the prey hits the ground, the height is 0 (y = 0). rx will be the value of x for which y = 0.

0 = -39 · x² + 156

-156/-39 = x²

x = 2.0 m

Then r = (2.0 m, -156.0 m)

The distance traveled will be:

$|r| =\sqrt{(2 m)^{2} + (156 m)^{2}} = 156.0 m$

8 0

3 years ago