I'll answer since there are no answers to refer to. A jovian planet is pretty much a planet that doesn't have a solid surface. It's a planet made up primarily of gases hydrogen, nitrogen, helium, methane and so on
Answer:
392 N
Explanation:
Draw a free body diagram of the rod. There are four forces acting on the rod:
At the wall, you have horizontal and vertical reaction forces, Rx and Ry.
At the other end of the rod (point X), you have the weight of the sign pointing down, mg.
Also at point X, you have the tension in the wire, T, pulling at an angle θ from the -x axis.
Sum of the moments at the wall:
∑τ = Iα
(T sin θ) L − (mg) L = 0
T sin θ − mg = 0
T = mg / sin θ
Given m = 20 kg and θ = 30.0°:
T = (20 kg) (9.8 m/s²) / (sin 30.0°)
T = 392 N
We can only corelate the object's weight with the amount of water it was able to displaced.
If the water displaced was around 400N, then the amount of liter displaced is around 400 N (kg*m/s²) / 9.8 m/s² (earth's gravitational pull) which is equals to ~40.81 liters which should be the objects mass as the best assumption (1kg = 1L). As there is no direct link between the water displaced and actual object weight.
A "light year" is not an amount of time.
It's an amount of distance ... the distance that light travels
through space in one year.
1 light year = 5,878,625,372,000 miles
(rounded to the nearest thousand miles)
1 light-year = 9,460,730,473,000 kilometers
(rounded to the nearest thousand kilometers)
Answer:
The answer is <em><u>6 m/s^2</u></em>.
Explanation:
by using the formula,
a = v-u/t
