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BlackZzzverrR [31]
3 years ago
7

a trolley of mass 20kg was originally at rest on a smoth horizontal surface. bu how much will it accelerate if a pulling force o

f 22N is applied on it horizontally?​
Physics
1 answer:
DochEvi [55]3 years ago
6 0

Answer:

just divide 22 N by 20 kg to get the acceleration in m/s2

Explanation:

I hope this is right-

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If the voltage across a circuit of constant resistance is doubled, the power dissipated by that circuit will
densk [106]

Answer:

The voltage will quadruple

Explanation:

The power dissipated in a circuit is given by

P=\frac{V^2}{R}

where

V is the voltage

R is the resistance

In this problem, the voltage across the circuit is doubled:

V' = 2V

So the new power dissipated is

P'=\frac{V'^2}{R}=\frac{(2V)^2}{R}=4\frac{V^2}{R}=4 P

so, the power dissipated will quadruple.

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3 years ago
Have a pH between 0-7.
Pavlova-9 [17]

Answer:

acidic

Explanation:

because the lower you go on the scale the more acidic it is and the closer to the middle the more neutral it is

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3 years ago
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The distance between earth and sun is 15000000km. Light takes 499 seconds to reach earth from sun. Calculate the speed of light
iVinArrow [24]

To solve the problem we must know about the relationship between Speed, distance, and Time.

<h3>What is the relationship between Speed, distance, and Time?</h3>

We know that sped, distance, and time all are in a relationship to each other. this relationship can be given as,

\rm{Speed = \dfrac{Distance}{Time}

The speed of the light is 30,060.12 km/sec.

Given to us

  • The distance between the earth and the sun is 15000000km
  • Light takes 499 seconds to reach earth from the sun.

We know that speed can be described as,

\rm{Speed = \dfrac{Distance}{Time}

Therefore,

<h3>What is the speed of the light?</h3>

\text{Speed of light} = \dfrac{\text{Distance between the earth and the sun}}{\text{Time taken by the light to travel the distance}}

Substitute the value,

\text{Speed of light} = \dfrac{15,000,000\ km}{499\ seconds}

\text{Speed of light} = 30,060.12\ km/sec

Hence, the speed of the light is  30,060.12 km/sec.

Learn more about Speed, distance, and Time:

brainly.com/question/15100898

7 0
2 years ago
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On a frictionless horizontal air table, puck A (with mass 0.254 kg ) is moving toward puck B (with mass 0.367 kg ), which is ini
irinina [24]

Answer:

v_a=0.8176 m/s

\Delta K=0.07969 J - 0.0849 J = -0.00521 J

Explanation:

According to the law of conservation of linear momentum, the total momentum of both pucks won't be changed regardless of their interaction if no external forces are acting on the system.

Being m_a and m_b the masses of pucks a and b respectively, the initial momentum of the system is

M_1=m_av_a+m_bv_b

Since b is initially at rest

M_1=m_av_a

After the collision and being v'_a and v'_b the respective velocities, the total momentum is

M_2=m_av'_a+m_bv'_b

Both momentums are equal, thus

m_av_a=m_av'_a+m_bv'_b

Solving for v_a

v_a=\frac{m_av'_a+m_bv'_b}{m_a}

v_a=\frac{0.254Kg\times (-0.123 m/s)+0.367Kg (0.651m/s)}{0.254Kg}

v_a=0.8176 m/s

The initial kinetic energy can be found as (provided puck b is at rest)

K_1=\frac{1}{2}m_av_a^2

K_1=\frac{1}{2}(0.254Kg) (0.8176m/s)^2=0.0849 J

The final kinetic energy is

K_2=\frac{1}{2}m_av_a'^2+\frac{1}{2}m_bv_b'^2

K_2=\frac{1}{2}0.254Kg (-0.123m/s)^2+\frac{1}{2}0.367Kg (0.651m/s)^2=0.07969 J

The change of kinetic energy is

\Delta K=0.07969 J - 0.0849 J = -0.00521 J

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3 years ago
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Answer:

1- C   2-B    3-B   - these are ur best answers

Explanation:

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