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3 years ago

5

Large electric fields in cell membranes cause ions to move through the cell wall. The field strength in a typical membrane is 1.

0 times 107 N/C. What is the magnitude of the force on a calcium ion with charge +e?

1 answer:

serg [7]3 years ago

6 0

Explanation:

The given data is as follows.

Electric field (E) = $1 \times 10^{7} N/C$

Charge (e) = $1.6 \times 10^{-19}$ C

Formula to calculate the magnitude of force is as follows.

F = qE

= $1.6 \times 10^{-19} \times 1 \times 10^{7} N/C$

= $1.6 \times 10^{-12} N$

Therefore, we can conclude that magnitude of the force on a calcium ion with charge +e is $1.6 \times 10^{-12} N$ .

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A mass of 267 g is attached to a spring and set into simple harmonic motion with a period of 0.176 s. If the total energy of the

Gnoma [55]

Answer:

(a) 7.1 m /sec

(b) 339.9 N/m

(c) 19.91 cm

Explanation:

We have given mass m = 267 gram = 0.267 kg

Time period T = 0.176 sec

Total energy of the oscillating system = 6.74 J

We know that energy is given by

(a) $Ke=\frac{1}{2}mv_{max}^2$

$6.74=\frac{1}{2}\times 0.267\times v_{max}^2$

$v_{max}=7.1m/sec$

(b) Now $\omega =\frac{2\pi }{T}=\frac{2\times 3.14}{0.176}=35.681rad/sec$

We know that $\omega =\sqrt{\frac{k}{m}}$

$35.68=\sqrt{\frac{k}{0.267}}$

$k=339.9N/m$

(c) We know that energy is given by

$E=\frac{1}{2}KA^2$

$6.74=\frac{1}{2}\times 339.9\times A^2$

$A=19.91cm$

4 0

2 years ago

Eukaryotic cells can be unicellular and multicellular true or false

dimaraw [331]

Yes, it can be unicellular and multicellular

8 0

3 years ago

What is the mathematical relationship among voltage current and resistance

loris [4]

Answer:

The relationship between voltage, current, and resistance is described by Ohm's law. This equation, i = v/r, tells us that the current, i, flowing through a circuit is directly proportional to the voltage, v, and inversely proportional to the resistance, r.

5 0

3 years ago

In a lab, four balls have the same velocities but different masses.

olya-2409 [2.1K]

Answer:

New Momentum of Ball B $=13.2 \frac{\mathrm{kgm}}{\mathrm{s}}$

<u>Explanation:</u>

Given:

Mass of Ball A=1kg

Mass of Ball B= 2kg

Mass of Ball C=5kg

Mass of Ball D=7kg

Velocities of A=B=C=D=2.2 $\frac{m}{s}$

Momentum of Ball A=2.2 $\frac{k g m}{s}$

Momentum of Ball B=4.4 $\frac{k g m}{s}$

Momentum of Ball C=11 $\frac{k g m}{s}$

Momentum of Ball D=15 $\frac{k g m}{s}$

To Find:

Change in Momentum When of Ball B gets tripled

Solution:

Though all balls have same velocity, thus we get

Velocities of A=B=C=D=2.2 $\frac{m}{s}$

Initial Momentum of Ball B=4.4 $\frac{k g m}{s}$

If the Mass of Ball B gets tripled;

We get New Mass of Ball B=3×Actual Mass of the ball

=3×2=6kg

Thus we get Mass of Ball B=6kg

According to the formula,

Change in momentum of Ball B $\Delta p=m \times \Delta v$

Where $\Delta p$ =change in momentum

m=mass of the ball B

$\Delta v$ =change in velocity ball B

And $\Delta v=v,$ since all balls, have same velocity

Thus the above equation, changes to

$\Delta p=m \times v$

Substitute all the values in the above equation we get

$\Delta p=6 \times 2.2$

$=13.2 \frac{\mathrm{kgm}}{\mathrm{s}}$

Result:

Thus the New Momentum of ball B $=13.2 \frac{\mathrm{kgm}}{\mathrm{s}}$

3 0

3 years ago

Read 2 more answers

A calorimeter is used to determine the specific heat capacity of a test metal. If the specific heat capacity of water is known,

denis23 [38]

Answer:

initial and final temperatures of both the water and metal, mass of the metal, and mass of the water

Explanation:

Heat lost by the metal, $Q = mc(t_{2} - t_{1})$

Heat gained by the water in the calorimeter, $Q_{w} = m_{w}c_{w}(t_{2w} - t_{1w})$

For energy to be conserved in the system, the heat lost by the metal will equal the heat gain by the water in the calorimeter.

$mc(t_{2} - t_{1}) = m_{w}c_{w}(t_{2w} - t_{1w})$

Where,

m is the mass of the metal

c is specific heat capacity of the metal

t₂ is the final temperature of the metal

t₁ is the initial temperature of the metal

$m_{w}$ is the mass of the water

$c_{w}$ is specific heat capacity of water

$t_{2w}$ is the final temperature of water

$t_{1w}$ is the initial temperature of water

From the question given, specific heat capacity of the water is known, the quantities to be measured are;

Initial and final temperatures of both the water and metal,

Mass of the metal, and mass of the water

8 0

3 years ago