Answer:
1/R = 1/R1 + 1/R2 + 1/R3
1/1 + 1/2 + 1/4 = 1 + .5 + .25 = 1.75
1/1.75 = .572
multiplying this by 100 gives us
R = 57.2 ohms
The smallest resistor (100 ohms) will draw the most current
(One can also use R = R1 R2 R3 / (R1 R2 + R1 R3 + R2 R3)
Answer:
a.
Explanation:
The orientation of the dipole has the greatest electric potential energy is when when the dipole moment and the electric field are anti parallel to each other at that time cosθ= -1
U = -pEcosθ
put θ=180
⇒cos180 = -1
Therefore, U = pE
Answer:
hot
Explanation:
cause the room temperature is higher
Answer
Mass m = 78 kg
Vertical height in each stage h = 11 m
(a).
Initial speed u = 0
Final speed v = 1.1 m / s
![v^2=u^2 + 2 as](https://tex.z-dn.net/?f=v%5E2%3Du%5E2%20%2B%202%20as)
![1.1^2 = 2 a \times 11](https://tex.z-dn.net/?f=1.1%5E2%20%3D%202%20a%20%5Ctimes%2011)
a = 0.055 m/s²
Work done
![W_a= m g h + \dfrac{1}{2}mv^2](https://tex.z-dn.net/?f=W_a%3D%20m%20g%20h%20%2B%20%5Cdfrac%7B1%7D%7B2%7Dmv%5E2)
![W_a= 78\times 9.8 \times 11 + \dfrac{1}{2} 78 \times 1.1^2](https://tex.z-dn.net/?f=W_a%3D%2078%5Ctimes%209.8%20%5Ctimes%2011%20%2B%20%5Cdfrac%7B1%7D%7B2%7D%2078%20%5Ctimes%201.1%5E2)
![W_a = 8408.4 + 47.19](https://tex.z-dn.net/?f=W_a%20%3D%208408.4%20%2B%2047.19)
![W_a = 8455.59 J](https://tex.z-dn.net/?f=W_a%20%3D%208455.59%20J)
(b).Work done
![W_b= mgh](https://tex.z-dn.net/?f=W_b%3D%20mgh)
W_b = 78× 9.8× 11
![W_b= 8408.4 J](https://tex.z-dn.net/?f=W_b%3D%208408.4%20J)
c)
Work done
![W= m g h + \dfrac{1}{2}m(v_f-v_i)^2](https://tex.z-dn.net/?f=W%3D%20m%20g%20h%20%2B%20%5Cdfrac%7B1%7D%7B2%7Dm%28v_f-v_i%29%5E2)
Where V = final speed
= 0
v = 1.1 m / s
for deceleration a = -0.055 m/s²
now,
![F_L = 56 (-0.055+9.8) = 545.72 N](https://tex.z-dn.net/?f=F_L%20%3D%2056%20%28-0.055%2B9.8%29%20%3D%20545.72%20N)
W_c = 545.75 × 11
![W_c = 6003.25 J](https://tex.z-dn.net/?f=W_c%20%3D%206003.25%20J)
Answer:
352,088.37888Joules
Explanation:
Complete question;
A hiker of mass 53 kg is going to climb a mountain with elevation 2,574 ft.
A) If the hiker starts climbing at an elevation of 350 ft., what will their change in gravitational potential energy be, in joules, once they reach the top? (Assume the zero of gravitational potential is at sea level)
Chane in potential energy is expressed as;
ΔGPH = mgΔH
m is the mass of the hiker
g is the acceleration due to gravity;
ΔH is the change in height
Given
m = 53kg
g = 9.8m/s²
ΔH = 2574-350 = 2224ft
since 1ft = 0.3048m
2224ft = (2224*0.3048)m = 677.8752m
Required
Gravitational potential energy
Substitute the values into the formula;
ΔGPH = mgΔH
ΔGPH = 53(9.8)(677.8752)
ΔGPH = 352,088.37888Joules
Hence the gravitational potential energy is 352,088.37888Joules