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MrRissso [65]
3 years ago
7

How do you translate The product of the difference of x and 3 and 4 into an algebraic expression

Mathematics
1 answer:
iragen [17]3 years ago
5 0

Answer:

3x-4

Step-by-step explanation:

I might be wrong but good luck.

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Fill in the blanks. In the 30-60-90 triangle below, side s has a length of____ and side r has a length of____.
horrorfan [7]
Answer:
square root of 3 and 2.
6 0
3 years ago
Exactly one pair of opposite sides parallel
liberstina [14]
QUICK ANSWER

A quadrilateral with exactly one pair of opposite parallel sides is called a trapezoid. As with all quadrilaterals, the sum of the interior angles of a trapezoid is always equal to 360 degrees

4 0
3 years ago
Read 2 more answers
What is the domain of f (x)X +2?x2-X-6O A. all real numbers except 2 and 3B. all real numbers except 2 and 3c. all real numbers
Vanyuwa [196]

Problem

f(x)=\frac{x+2}{x^2-x-6}

Solution

For this case we want to find the domain for this case and we can analyze the denominator on this case because cannot be equal to 0, so we can set up this:

x^2-x-6\ne0

If we factorize we got:

(X-3)(x+2)=0

So then we have X=3 and X=-2

With these results we can conclude that the value of x cannot be 3 or -2 because then the function will be not defined

And the best solution is:

A. all real numbers except -2 and 3

3 0
1 year ago
Simplify the expression using<br> order of operations<br> 12 (10-5) - 40 + (4+1)
Rasek [7]

ans is 25

Step-by-step explanation:

12(10-5)-40+(4+1)

=12 of 5 - 40 + 5

= 60 - 40 +5

=60 +5 - 40

=65-40

=25

6 0
3 years ago
Read 2 more answers
Sketch the region bounded by the curves x=y3,x=1, and y=0 then find the volume of the solid generated by revolving this region a
NeX [460]

According to the question, the region is bounded by the curve with the given data as x = y^{3} , x=1, y=0.

To compute the volume of the solid, use the disk method. The given object is rotated along the horizontal axis with the disk cross sectional area and the volume can be written as:

v=\int\limits^a_b {\pi x^{2} } \, dx

As per question, when x = 1 then the value of y is: y = 1

Now, substituting calculated values in the expression:

v=\int\limits^a_b {\pi x^{2} } \, dx=v=\int\limits^0_1 {\pi x^{2} } \, dx

Substitute the value of the variable 'x':

Therefore, the expression can be written as:

v=\int\limits^a_b {\pi x^{2} } \, dx=v=\int\limits^0_1 {\pi x^{2} } \, dx=\int\limits^0_1 {\pi (y^{3}) ^{2} } \, dx=\frac{\pi }{7}=0.448

To learn more about the integration from the given link:

<u>brainly.com/question/988162</u>

#SPJ4

5 0
1 year ago
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