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4 years ago

What does the x represent on a motion map?

Physics

2 answers:

kompoz [17]4 years ago

6 0

<span>A. reference point
just took the quiz and it was correct</span>

il63 [147K]4 years ago

5 0

Answer;

-Reference point

The x represents the reference point on a motion map.

Explanation;

-Motion maps are another way to represent the motion of an object. (other representations are graphical and mathematical models).

-Motion maps are a visual way to represent an object’s motion at various time

-. A reference point is a place or object used for comparison to determine if something is in motion. An object is in motion if it changes position relative to a reference point.

-The relationships between motion and reference point is that When an object changes position over time relative to a reference point, the object is in motion. This means that there relationship is they are similar.

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Car A starts out traveling at 35.0 km/h and accelerates at 25.0 km/h2 for 15.0 min. Car B starts out traveling at 45.0 km/h and

lawyer [7]

1 kilometre=1000 metre

1 hour = 3600 second

$1\ km/hr=\frac{1000}{3600} m/s$

$1\ km/hr=\frac{5}{18} m/s$

The initial velocity of car A is 35.0 km/hr i.e

$35.0\ km/hr=35*\frac{5}{18} m/s$

= 9.72 m/s

The initial velocity of car B is 45 km/hr =12.5 m/s

The initial velocity of car C is 32 km/hr = 8.89 m/s

The initial velocity of car D is 110 km/hr=30.56 m/s

The acceleration of car A is given as $25\ km/hr^2$

$=\ 25*\frac{1000}{3600*3600} m/s^2$

$=0.00192901234 m/s^2$

The time taken by car A = 15 min.

From equation of kinematics we know that-

v= u+at [Here v is the final velocity and a is the acceleration and t is the time]

Final velocity of A, v = 9.72 m/s +[0.00192901234×15×60]m/s

=11.456111106 m/s

The acceleration of B is given as $15\ km/hr^2$

$=0.00115740740740 m/s^2$

The time taken by car B =20 min

The final velocity of B is -

v= u+at

= u-at [Here a is negative due to deceleration]

=12.5 m/s +[0.0011574074074×20×60]

=13.8888888.....

=13.9

The acceleration of C is given as $40\ km/hr^2$

$=\ 0.003086419753 m/s^2$

The time taken by car C =30 min

The final velocity of C is-

v = u+at

=8.89 m/s+[0.003086419753×30×60] m/s

=14.4455555555..m/s

=14.45 m/s

The car C is decelerating.The deceleration is given as- $60\ km/hr^2$

$=0.0046296296296m/s^2$

The time taken by car D= 45 min.

The final velocity of the car D is-

v =u+at

=30.56 -[0.00462962962962×45×60]m/s

=18.06 m/s

Hence from above we see that the magnitude of final velocity car C and B is close to 15 m/s. The car C is very close as compared to car B.

3 0

3 years ago

Explain how an electrical wet cell functions.

Fynjy0 [20]

The chemical reaction causes electricity to flow through the terminals to the load attached. Some of the acid in the battery remains on the plates as it flows through. When the battery is recharged the acid is returned to the liquid solution to provide more power later.

3 0

4 years ago

What is Earth's role in the hierarchy of organization within the universe?

enot [183]

<span>Earth's position is the Big Bang. We are located in one of the Milky Way's arms. Slowly the planets get further away from each other. It's the third planet from the sun,</span>

3 0

3 years ago

A ceiling fan with 90-cm-diameter blades is turning at 64 rpm . Suppose the fan coasts to a stop 28 s after being turned off. Wh

mixas84 [53]

Answer:

the speed of the tip of a blade 10 s after the fan is turned off is 16.889 m/s.

Explanation:

Given;

diameter of the ceiling fan, d = 90 cm = 0.9 m

angular speed of the fan, ω = 64 rpm

time taken for the fan to stop, t = 28 s

The distance traveled by the ceiling fan when it comes to a stop is calculated as;

$d = vt = \omega r\times t= ( \frac{64 \ rev}{\min} \times \frac{2 \pi \ rad}{rev} \times \frac{1 \min}{60 \ s} \times 0.9 \ m) \times 28 \ s\\\\d = 168.89 \ m$

The speed of the tip of a blade 10 s after the fan is turned off is calculated as;

$v = \frac{d}{t} \\\\v = \frac{168.89}{10} \\\\v = 16.889 \ m/s$

Therefore, the speed of the tip of a blade 10 s after the fan is turned off is 16.889 m/s.

4 0

3 years ago

How many heat is needed to melt 1.5kg of ice and then to raise the temperature of the resulting water 50 degree Celsius

BabaBlast [244]

Answer:

• The amount of heat required to melt ice and raise the temperature of water T^oCToC is

Q=mL_f+mc\Delta TQ=mLf+mcΔT

Here m=1.5 kgm=1.5kg

L_f=3.33*10^5 J/kgLf=3.33∗105J/kg is Latent heat of fusion of ice.

c=4186 J/kg.^oCc=4186J/kg.oC is heat capacity of water.

\Delta T=50 ^oC-0^oC=50^oCΔT=50oC−0oC=50oC

So,

Q=(1.50)[3.33*10^5 +(4186)(50)]=8.13*10^5 JQ=(1.50)[3.33∗105+(4186)(50)]=8.13∗105J

4 0

3 years ago