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MrRissso [65]
3 years ago
6

A roadway for stunt drivers is designed for racecars moving at a speed of 40 m/s. A curved section of the roadway is a circular

arc of 230 m radius. The roadway is banked so that a vehicle can go around the curve with the friction force from the road equal to zero. At what angle is the roadway banked?
Physics
1 answer:
Fynjy0 [20]3 years ago
3 0

Answer:

Bank angle = 35.34o

Explanation:

Since the road is frictionless,

Tan (bank angle) = V^2/r*g

Where V = speed of the racing car in m/s, r = radius of the arc in metres and g = acceleration due to gravity in m/s^2

Tan ( bank angle) = 40^2/(230*9.81)

Tan (bank angle) = 0.7091

Bank angle = tan inverse (0.7091)

Bank angle = 35.34o

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Select the true statements: check all that apply check all that apply oxidizing agents can convert co into co2. a reducing agent
andrew11 [14]

Answer:

1.) True

2.) True

3.) False

Explanation:

1.) Oxidizing agents can convert co into co2.

This is true

Carbon monoxide burns in the oxygen to produce carbon dioxide

2.) A reducing agent gets oxidized as it reacts.

This is true

Because it loses electrons and is oxidized in a chemical reaction. 

3.) If something is reduced, it is formally losing electrons.

This is false.

If something is reduced, it is gaining electrons.

7 0
3 years ago
The "steam" above a freshly made cup of instant coffee is really water vapor droplets condensing after evaporating from the hot
KiRa [710]

Answer:

T_{f} = 85.7 ° C

Explanation:

For this exercise we will use the calorimetry heat ratios, let's start with the heat lost by the evaporation of coffee, since it changes from liquid to vapor state

      Q₁ = m L

Where m is the evaporated mass (m = 2.00 103-3kg) and L is 2.26 106 J / kg, where we use the latent heat of the water

     Q₁ = 2.00 10⁻³ 2.26 10⁶

     Q1 = 4.52 10³ J

Now the heat of coffee in the cup, which does not change state is

     Q coffee = M c_{e} ( T_{f} -T_{i})

Since the only form of energy transfer is terminated, the heat transferred is equal to the evaporated heat

    Qc = - Q₁

    M ce (T_{f} -T_{i}) = - Q₁

The coffee dough left in the cup after evaporation is

    M = 250 -2 = 248 g = 0.248 kg

   T_{f} -Ti = -Q1 / M c_{e}

   T_{f} = Ti - Q1 / M c_{e}

Since coffee is essentially water, let's use the specific heat of water,

    c_{e}= 4186 J / kg ºC

Let's calculate

     T_{f} = 90.0 - 4.52 103 / (0.248 4.186 103)

     T_{f} = 90- 4.35

     T_{f} = 85.65 ° C

     T_{f} = 85.7 ° C

5 0
3 years ago
Set the radius to 2.0 m and the velocity to 1.0 m/s. Keeping the radius the same, record the magnitude of centripetal accelerati
jek_recluse [69]

Answer:

a=4\ m/s^2

Explanation:

Given that,

Radius, r = 2 m

Velocity, v = 1 m/s

We need to find the magnitude of the centripetal acceleration. The formula for the centripetal acceleration is given by :

a=\dfrac{v^2}{r}\\\\a=\dfrac{(2)^2}{1}\\\\=4\ m/s^2

So, the magnitude of centripetal acceleration is 4\ m/s^2.

5 0
2 years ago
How would the composition of an atom change if both the atomic number and mass number each increase by one? A) The atom would ha
weqwewe [10]
Choice-B is the correct one. 

-- The atomic number is the number of protons in the nucleus.
-- Each proton in the nucleus is usually matched by one electron in the 'cloud'.
-- The addition of a proton OR a neutron increases the mass number by 1 .
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8 0
3 years ago
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8 0
2 years ago
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