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Flauer [41]
3 years ago
7

Inside most ball-point pens is a small spring that compresses as the pen is pressed against the paper. If a force of 0.1 N compr

esses the pen's spring a distance of 0.005 m, what is the spring constant of the tiny spring?
Physics
1 answer:
AnnZ [28]3 years ago
8 0

Answer:

20 N/m

Explanation:

From the question,

The ball-point pen obays hook's law.

From hook's law,

F = ke............................ Equation 1

Where F = Force, k = spring constant, e = compression.

Make k the subject of the equation

k = F/e........................ Equation 2

Given: F = 0.1 N, e = 0.005 m.

Substitute these values into equation 2

k = 0.1/0.005

k = 20 N/m.

Hence the spring constant of the tiny spring is 20 N/m

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madreJ [45]

Answer:

Kilometers\ in\ 1\ Orbit=\frac{1.28*10^9 Km}{3.7*10^4orbits}

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Explanation:

Given Data:

Numbers of times Telescope cycled around the earth in 6 years=37,000 times

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Find:

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Solution:

Kilometers in 37,000 Orbits=1,280,000,000 Km

Kilometers in 1 Orbit=1,280,000,000/37,000

In Scientific Notation:

Kilometers\ in\ 3.7*10^4\ Orbits=1.28*10^9 Km

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Kilometers in 1 Orbit=34594.594 Km

Kilometers in 1 Orbit in Scientific notation:

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The correct answer is option D i.e. A and C

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The correct answer is option D i.e. A and C

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tamaranim1 [39]

Answer: 585 J

Explanation:

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