The volume of a triangular prism is V = 1/2 x a x c x h where a is height of the triangle, c is the base of the triangle and h is the height of the prism.
120 = 1/2 x a x c x h; we write a from the previous equation in terms of c and h thus,
a = 240 / ( c x h)
If the dimensions where halved then a = a/2 ; c = c/2 ; h=h/2
We use the volume formula again and substitute the given values to find the new volume,
V = 1/2 x a/2 x c/2 x h/2
Substitute the previously determined a term,
V = 1/2 x (240/2ch) x c/2 x h/2
We cancel and evaluate the constants therefore the new volume is,
V= 15 cm^3
Answer:
It's the first one I think
Answer:
The radius of can is approximately 3.82 cm.
Step-by-step explanation:
We are given the following in the question:
Surface area of can = 332 square cm
Height of can = 10 cm
We have to find the radius of circular top.
Formula:
Surface area of can = Surface area of cylinder

Since, the radius cannot be negative.
The radius of can is approximately 3.82 cm.
Answer:
C) 0.880
B) 0.075
Step-by-step explanation:
If the professor forgets to set the alarm
Probability = 0.1,
Wakes up in time probability = 0.25.
If the professor sets the alarm
Probability = 1 - 0.1 = 0.9
Wake up in time probability = 0.95.
A.)
The probability that professor Moore wakes up in time to make his first class tomorrow
Probability = ( Forgets to set alarm probability x Wakes up in time )+ ( Sets the alarm probability x Wakes up in time ) = ( 0.1 x 0.25 ) + ( 0.9 + 0.95 ) = 0.88
B.)
Late in the class
Set the Alarm Probability = 0.1
Wakes up late probability = 1 - 0.25 = 0.75
Professor Sets the alarm probability = Set the Alarm Probability x Wakes up late probability = 0.1 x 0.75 = 0.075
Answer:
<h2>(-2, -1)</h2>
Step-by-step explanation:
Convert the inequality to the form y > mx + b:
3x + y > -8 <em>subtract 3x from both sides</em>
y > -3x - 8
Put the coordinates of the points to the inequality and check:
for (-3, 0)
0 > -3(-3) - 8 → 0 > 9 - 8 → 0 > 1 FALSE
for (-2, -1)
-1 > -3(-2) - 8 → -1 > 6 - 8 → -1 > -2 TRUE
for (0, -10)
-10 > -3(0) - 8 → -10 > 0 - 8 → -10 > -8 FALSE
for (2, -16)
-16 > -3(2) - 8 → -16 > -6 - 8 → -16 > -14 FALSE