Answer:
Oxidizing agent - CrO4^2-
Reducing agent- N2O
Explanation:
Let us look at the equation closely;
CrO4^2- (aq) + 3N2O(g) ------------> Cr^3+ (aq) + 3NO(g) [acidic]
The reduction half equation is;
CrO4^2- (aq) + 3e -------->Cr^3+ (aq)
Oxidation half equation is;
3N2O(g) ------>3 NO(g) +3 e
Note that the oxidizing agent participates in the reduction half equation while the reducing agent participates in the oxidation half equation as seen above.
Answer:
Explanation:
When looking at a chemical reaction, the substance present before the reaction takes place are called the (5)
REACTANT
and the substance produced after the reaction are the (6).
PRODUCT
know through the Law of Conservation of (7)
MATTER
that nothing is created or destroyed. This is reflected in a (8
BALANCED
chemical equation, where the NUMBER OF atoms of each element on each side of the arrow is (9)-
equal
or the same.
REMEMBER: WHEN BALANCING EQUATIONS YOU CANNOT CHANGE THE SUBSCRIPTS OF THE COMPOUNDS, YOU CAN ONLY SHOW BY THE COEFFICIENTS HOW MANY MOLECULES YOU HAVE!
Follow your nose to the fruity taste of chows recharge the heart then follow your heart good luck my friend
