Question

Water has a heat of fusion of about 300J/gram and a heat capacity for liquid water of a about 4J/gC. How much heat is needed to warm a 10 gram block of solid ice at 0 degree celcius to 10 degree celcius?
A. 30.4 KJ
B. 3.4 KJ
C. 0.3 KJ
D. 3.04 KJ

Answer 1

Answer:

The total heat required is 3.4 kJ

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

There is a direct proportional relationship between heat and temperature. So, the amount of heat a body receives or transmits is determined by:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case you know;

• Q= ?

• c= 4 $\frac{J}{g*C}$

• m= 10 g
• ΔT= Tfinal - Tinitial= 10 C - 0 C= 10 C

Replacing:

$Q= 4\frac{J}{g*C} *10 g * 10 C$

Solving:

Q1= 400 J

On the other hand, you must determine the heat required to convert 0 ∘ C of ice to 0 ∘ C of liquid water by:

Q2=m*heat of fusion

Q2=10 g* 300 $\frac{J}{g}$

Q2= 3,000 J

The total heat required is:

Q= Q1 + Q2= 400 J + 3,000 J

Q= 3,400 J= 3.4 kJ (1 kJ= 1,000 J)

The total heat required is 3.4 kJ