Answer:
See explanation.
Explanation:
Hello,
In this case, we could have two possible solutions:
A) If you are asking for the molar mass, you should use the atomic mass of each element forming the compound, that is copper, sulfur and four times oxygen, so you can compute it as shown below:
That is the mass of copper (II) sulfate contained in 1 mol of substance.
B) On the other hand, if you need to compute the moles, forming a 1.0-M solution of copper (II) sulfate, you need the volume of the solution in litres as an additional data considering the formula of molarity:
So you can solve for the moles of the solute:
Nonetheless, we do not know the volume of the solution, so the moles of copper (II) sulfate could not be determined. Anyway, for an assumed volume of 1.5 L of solution, we could obtain:
But this is just a supposition.
Regards.
> 2,000
mL of a 5.0 × 10–5% (w/v) sucrose solution
5.0 × 10–3
g/mL * 2000 mL * (1 mol / 342.30 g) = 0.0292 mol
<span>
> 2,000 mL of a 5.0 ppm sucrose solution</span>
5 grams /
1000000 mL * 2000 mL* (1 mol / 342.30 g) = 0.0000292 mol
<span>
> 20 mL of a 5.0 M sucrose solution </span>
5.0 M *
0.020 L = 0.1 mol
Answer:
<span>2,000 mL
of a 5.0 ppm sucrose solution</span>
Answer:
lava is coming from the crust
Explanation:
volcano's explode with lava because the crust pushes it out
Answer: , 4 molecules of ammonia, NH3(g) is produced; 2 molecules of ammonia, NH3(g) is produced respectively
Explanation:
The balanced equation is stated below N2(g) + 3H2(g) → 2NH3(g)
1 mole of N2(g) reacts with 3 moles of H2(g) to yield 2 moles of NH3(g)
1) If 2 molecules of N2 react, then the balanced equation will be
2N2(g) + 6H2(g) → 4NH3(g)
Thus, 4 molecules of ammonia, NH3(g) is produced
2) If 3 molecules of H2 react, then the balanced equation will be
N2(g) + 3H2(g) → 2NH3(g)
Thus, 2 molecules of ammonia, NH3(g) is produced
