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3 years ago

12

The circumference of a circle changes from 20 to 4 after dilation what is the scale factor

1 answer:

Vitek1552 [10]3 years ago

3 0

Answer:

1/5

Step-by-step explanation

20 * 1/5 = 4

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Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu

olchik [2.2K]

Answer:

a) $s^2 =30^2 =900$

b) $\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

c) $23.818 \leq \sigma \leq 41.112$

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in the variability in the number of rooms occupied per day during a particular season of the year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

$s^2 =30^2 =900$

Part b

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

The degrees of freedom are given by:

$df=n-1=20-1=19$

Since the Confidence is 0.90 or 90%, the significance $\alpha=0.1$ and $\alpha/2 =0.05$ , the critical values for this case are:

$\chi^2_{\alpha/2}=30.144$

$\chi^2_{1- \alpha/2}=10.117$

And replacing into the formula for the interval we got:

$\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

Part c

Now we just take square root on both sides of the interval and we got:

$23.818 \leq \sigma \leq 41.112$

5 0

3 years ago

Jan graphed her house and the local parks on a coordinate plane. Her house is located at (-5, 6), Park A is at (4, 6), and Park

Ulleksa [173]

C the park B is the furthest at 11 blocks away

8 0

2 years ago

Read 2 more answers

What value of y satisfies the system of equations:<br><br> y=-6x+2<br><br> y=x^2+11

Nataly [62]

Answer:

The value of y that satisfies the system of equations is 20

Step-by-step explanation:

we have

$y=-6x+2$

$y=x^{2}+11$

we know that

The solution of the system of equations is the intersection point both graphs

using a graphing tool

the intersection point is (-3,20)

see the attached figure

therefore

The value of y that satisfies the system of equations is 20

8 0

2 years ago

Find the slope between the point (a+b,4m-n) and (a-b,m+2n)

umka2103 [35]

Answer:

m = -3m+3n/-2b

Step-by-step explanation:

Slope is expressed as;

m = y2-y1/x2-x1

Given the coordinates (a+b,4m-n) and (a-b,m+2n)

m = (m+2n)-(4m-n)/(a-b)-(a+b)

m = m+2n-4m+n/a-b-a-b

m = m-4m+2n+n/a-a-b-b

m = -3m+3n/-2b

Hence the required slope is m = -3m+3n/-2b

6 0

2 years ago

What is the approximate volume of the cylinder use 22/7 for 3.14 round to the nearest whole number

erastova [34]

Answer:

the formula for a cylinder is πr^2•h

Step-by-step explanation:

just plug in the numbers, and you can change π to 3.14 for an approximate answer!

hopefully this helps you!

5 0

2 years ago

Read 2 more answers