A medical center observed that about 60% of its morning appointments were with elderly patients. The table shows the results of
a simulation used to represent the scenario. The numbers 0 to 5 represent appointments with elderly patients, and the numbers 6 to 9 represent appointments with other patients.
1 3 8 1 6 9 2 8 6 5 7 7 2 2 4
7 6 6 2 0 7 3 2 0 3 4 3 5 0 4
9 5 8 4 9 7 8 5 7 4 2 5 8 8 1
1 0 0 9 9 9 3 2 1 6 6 2 6 8 8
1 3 7 8 8 9 5 6 0 9 7 2 5 5 4
7 5 5 5 8 0 8 1 7 1 7 4 6 3 9
7 1 0 1 8 2 1 1 6 6 9 1 4 1 5
4 0 9 3 9 4 7 0 2 8 9 0 4 3 2
9 3 7 6 3 6 9 0 8 3 7 2 2 9 8
7 0 5 4 8 3 8 2 0 6 9 4 5 3 9
The estimated probability that it will take at least four patients to find one who is not an elderly patient is
. The estimated probability that exactly two of three randomly selected morning appointments are with elderly patients is
.
1 answer:
50% because of your question so the answer is 50%
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Answer: The picture contains the answer and the steps
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Answer:
The answer is 20.0855
Step-by-step explanation:
<u>Ca</u><u>l</u><u>c</u><u>ulate the approximate </u><u>value</u>
e³ = 20.0855
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About 29%.
35 - 25 = 10, or the amount of change
10 / 35 = .285, or the amount of change over total
