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2 years ago

(18x² – 3x²+x-1) ÷ (x² – 4)

Mathematics

1 answer:

Dimas [21]2 years ago

7 0

Answer:

x = sqrt(61)/30 - 1/30 or x = -1/30 - sqrt(61)/30

Step-by-step explanation:

Solve for x:

(15 x^2 + x - 1)/(x^2 - 4) = 0

Multiply both sides by x^2 - 4:

15 x^2 + x - 1 = 0

Divide both sides by 15:

x^2 + x/15 - 1/15 = 0

Add 1/15 to both sides:

x^2 + x/15 = 1/15

Add 1/900 to both sides:

x^2 + x/15 + 1/900 = 61/900

Write the left hand side as a square:

(x + 1/30)^2 = 61/900

Take the square root of both sides:

x + 1/30 = sqrt(61)/30 or x + 1/30 = -sqrt(61)/30

Subtract 1/30 from both sides:

x = sqrt(61)/30 - 1/30 or x + 1/30 = -sqrt(61)/30

Subtract 1/30 from both sides:

Answer: x = sqrt(61)/30 - 1/30 or x = -1/30 - sqrt(61)/30

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Here's a graph of a linear function. Write the

nikklg [1K]

Answer:

y= 3/2x + 1

Step-by-step explanation:

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2 years ago

Recall that m(t) = (1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500g sample of phosphorus-32 decays

katrin2010 [14]

The question is incomplete, here is the complete question:

Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.

Answer: The half life of the sample of phosphorus-32 is $14.28days^{-1}$

Step-by-step explanation:

The equation used to calculate the half life of the sample is given as:

$m(t)=m_o(1/2)^{t/h}$

where,

m(t) = amount of sample after time 't' = 356 g

$m_o$ = initial amount of the sample = 500 g

t = time period = 7 days

h = half life of the sample = ?

Putting values in above equation, we get:

$356=500\times (\frac{1}{2})^{7/h}\\\\h=14.28days^{-1}$

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3 years ago

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liberstina [14]

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2 years ago

Solve the system by substitution. 4y = 5x -10y =-50

Trava [24]

Answer:

$x = -20 ; y =-5$

Step-by-step explanation:

Eqn. 1 ----> 4y = x

Eqn. 2 ----> 5x-10y = -50

(Simplifying eqn.2 further)

$=>5(x-2y)=-50$

$=>x-2y=\frac{-50}{5} =-10$

(Substituting the value of x from eqn. 1)

$=>4y-2y=-10$

$=>2y=-10$

$=>y =\frac{-10}{2} =-5$

Now, substituting the value of y in eqn. 1 ,

$x = 4*(-5)=-20$

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2 years ago

Which of the following statements best describes the graph of 3x − 2y = 4?

tigry1 [53]

B.) It is a straight line joining the points (0, −2), (2, 1), and (−2, −5).

[ It is because x- & y-coordinates are valid in this situation ]

Hope this helps!

6 0

3 years ago

Read 2 more answers

(18x² – 3x²+x-1) ÷ (x² – 4)​

(18x² – 3x²+x-1) ÷ (x² – 4)