Answer:
The electric field will be decreased by 29%
Explanation:
The distance between point P from the distance z = 2.0 R
Inner radius = R/2
Outer raidus = R
Thus;
The electrical field due to disk is:
)
Similarly;
However; the relative difference is:
![\dfrac{\hat {k_a} - \hat {k_b}}{\hat {k_a} }= \dfrac{E_a -E_a + \dfrac{\sigma}{2 \varepsilon_o \Big[1 - \dfrac{2.0 \ R}{\sqrt{(2.0 \ R)^2 + (\dfrac{R}{2})^2}} \Big] } } { \dfrac{\sigma}{2 \varepsilon_o \Big [ 1 - \dfrac{2.0 \ R}{\sqrt{ (2.0 \ R)^2 + (R)^2}} \Big] }}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Chat%20%7Bk_a%7D%20-%20%5Chat%20%7Bk_b%7D%7D%7B%5Chat%20%7Bk_a%7D%20%7D%3D%20%5Cdfrac%7BE_a%20-E_a%20%2B%20%5Cdfrac%7B%5Csigma%7D%7B2%20%5Cvarepsilon_o%20%20%5CBig%5B1%20-%20%5Cdfrac%7B2.0%20%5C%20R%7D%7B%5Csqrt%7B%282.0%20%5C%20R%29%5E2%20%2B%20%28%5Cdfrac%7BR%7D%7B2%7D%29%5E2%7D%7D%20%5CBig%5D%20%7D%20%7D%20%7B%20%5Cdfrac%7B%5Csigma%7D%7B2%20%5Cvarepsilon_o%20%5CBig%20%5B%201%20-%20%5Cdfrac%7B2.0%20%5C%20R%7D%7B%5Csqrt%7B%20%282.0%20%5C%20R%29%5E2%20%2B%20%28R%29%5E2%7D%7D%20%5CBig%5D%20%7D%7D)

Answer: 53125joules
Explanation: The formula for kinetic energy is 1/2mv^2.
So we would have
1/2[(170)(25x25)]=53125
Answer:
W= 1812.6 J
Explanation:
Work (W) is defined as the scalar product of force F by the distance (d) the body travels due to this force.
W= F*d* cosα Formula ( 1)
Where:
F is the force in Newtons (N)
d is the displacemente in meters (m)
α : Angle formed between force and displacement
Data
F = 10 N
d = 200 m
α = 25°
Work done by the pulling force while the passenger walks 200 m
We replace data in the formula (1)
W= F*d* cosα
W= (10 N)*(200 m)* cos25°
W= 1812.6 (N*m)
W= 1812.6 J
No. It has no acceleration, which just means that the forces acting on it are equal and opposite, not that there are no forces exerted on it.
But if you're talking about the resulting Net Force, then yes you can conclude there is no Net Force acting on an object with no acceleration.
Kinetic energy is related to an object's mass and velocity. The greater the velocity, the greater its kinetic energy will be if the mass remains constant. (so, the 10 m/s one)