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2 years ago

9

Si un automóvil va viajando y por la cantidad de tráfico, avanza, se detiene, acelera, baja la velocidad, se detiene y luego sig

ue. Podemos decir que ese tipo de movimiento es:
ayuda por favor es PARA HOY

1 answer:

Fynjy0 [20]2 years ago

6 0

Answer:

english please

Explanation:

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A mechanic jacks up the front of a car to an angle of 8.0° with the horizontal in order to change the front tires. the car is 3.

SOVA2 [1]

<span>First draw a free-body diagram. Torque T = Force F x Distance d where force is the component of gravitational force g and d is the lever arm distance to the pivot point. Since the pivot point is at the back tire we subtract that from the length of the car resulting in d = 1.12 - 0.40 = 0.72 meters = d. We are interested in the perpendicular component of the force exerted on the car jack so use sin 8 degrees then T=1130 kg x 9.81 m/s^2 x sin(8 degrees) x0.72 m = 1,110.80 Newton-meters</span>

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3 years ago

How are magnets used in modern technology?

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2 years ago

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A car travels around an oval racetrack at constant speed. The car is accelerating:________.

bija089 [108]

Answer:

1A,2D,3B

Explanation:

hope this helps

4 0

3 years ago

A stoppered test tube traps 25.0 cm3 of air at a pressure of 1.00 atm and temperature of 18OC. The cylindrically shaped stopper

storchak [24]

Explanation:

The pressure of an object is calculated as follows: $P = \frac{F}{A}$

The area of test tube stopper is A= π $r^{2}$

Since radius is half the diameter we have the following:

R = $\frac{1.20 cm}{2}$ = 0.60 cm

Thus the area of the test tube becomes:

A = π $( 0.60 Cm)^{2}$

= π $(0.006 m) ^{2}$

= 1.14 * $10^{-4} m^{2}$

Now the force from the outside of the tube.

$F_{out} = P_{out} A$

= $( 1.013 * 10^{5} Pa ) ( 1.14 * 10^{-4} m^{2} )$

= 11.55N

The net upward force on the stopper is equal to the difference of force exerted by pressure from inside of the tube and that from the outside.

$F_{Net} = F_{In} - F_{Out}$

$F_{In} = F_{Net} + F_{Out}$

$F_{In} = 11.5N + 11.55N$

= 23.1 N

8 0

3 years ago

I need help on this question!!

mr_godi [17]

Answer:

$\boxed {\boxed {\sf 6000 \ Joules}}$

Explanation:

Work is the product of force and distance.

$W=F*d$

The force is 500 Newtons and the couch is raised 12 meters above the ground.

Substitute these values into the formula.

$W=500 \ N * 12 \ m$

Multiply.

$W=6000 \ N*m$

1 Newton meter is equal to 1 Joule.
So, our answer of 6000 N*m equals 6000 J

$W= 6000 \ J$

The work done to move a 500 Newton couch 12 meters is <u>6000 Joules</u>. Therefore, choice D is correct.

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2 years ago

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