Question

(60 points to best answer) (asap please and thank you)

Answer 1

Answer: $83.\overline{3}\text{ feet}$

Step-by-step explanation:

Since, In the given diagram,

The sides of the triangles ABC and EDC are,

BC = 62 feet, DC = 93 feet and DE = 125 feet(given)

And, angles B and D are right angles,

⇒ $\angle ABC\cong \angle EDC$

$\text{Also, } \angle ACB\cong \angle ECD$    ( Vertically opposite angles )

By AA similarity postulate,

$\triangle ABC\sim \triangle EDC$

The sides of similar triangles are in same proportion ,

⇒  $\frac{AB}{ED}=\frac{BC}{DC}$

⇒  $AB \times DC = BC \times ED$

⇒  $AB = \frac{BC.ED}{DC}$

By substituting the values,

We get,

⇒  $AB = \frac{62\times 125}{93}$

⇒  $AB = \frac{7750}{93}=83.\overline{3}\text{ feet}$