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mrs_skeptik [129]
3 years ago
10

A highly concentrated solution from which dilutions are typically made for laboratory used is called a what?

Chemistry
1 answer:
Komok [63]3 years ago
4 0
A stock solution is the most concentrated
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What is the method of seperating inmisible liquid<br>​
nikitadnepr [17]
Decantation is a process for the separation of mixtures of immiscible liquids or of a liquid and a solid mixture such as a suspension.
6 0
2 years ago
If a question cannot be tested or observed it cannot be answered by science? True or false??
Triss [41]

the answers going to  be false

3 0
3 years ago
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A 10% bleach solution for disinfecting countertops can be prepared by: a. weighing the bleach and the water b. weight to volume
Ierofanga [76]

Answer:

The correct answer is - c. adding 10 mL bleach to 90 mL water.

Explanation:

To prepare a effective disinfecting solution to clean the countertops is a bleasce solution of 10% solution of bleach. The ten percent of the bleach solution means there are one volve of bleach and 9 volume of clean water in this solution.

So, preparing the 1/10 or ten percent solution is where adding 10 ml of bleach which is diluted to 90 ml clean water. This diluted solution can be use as disinfecting solution.

3 0
2 years ago
Determine the pH of 0.050 M HCN solution. HCN is a weak acid with a Ka equal to 4.9 x 10-10<br> DONE
nadezda [96]

Answer:

The pH of the solution is 5.31.

Explanation:

Let "\alpha is the dissociation of weak acid - HCN.

The dissociation reaction of HCN is as follows.

                  HCN+H_{2}O\rightarrow H_{3}O^{+}+CN^{-}

Initial                  C                         0            0

Equilibrium        c(1- \alpha)              c\alpha c\alpha

Dissociation constant = Ka= c\alpha \times \frac{c\alpha}{c(1-\alpha)}

=\frac{c\alpha^{2}}{(1-\alpha)}

In this case weak acids \alpha is very small so, (1-\alpha ) is taken as 1.

Ka=C\alpha^{2}

\alpha=\sqrt\frac{ka}{c}

From the given the concentration = 0.050 M

Substitute the given value.

\alpha=\sqrt\frac{4.9\times 10^{-10}}{0.05}=9.8\times 10^{-4}

[H_{3}O^{+}]=c\alpha

[H_{3}O^{+}]=0.05\times 9.8\times 10^{-4}= 4.9\times10^{-6}

pH= -log[H_{3}O^{+}]

=-log[4.9\times10^{-6}]

=6-log 4.9= 5.31

Therefore, The pH of the solution is 5.31.

7 0
3 years ago
Read 2 more answers
What volume, in milliliters, of a 0.140 M solution of KCl contains 2.65 g of the compound?
marishachu [46]

Answer:

Calculate moles KCl: 2.55 g / 74.55 g/mol = 0.0342 moles KCl

Volume KCl = 0.0342 mol X (1 L/0.150 mol) = 0.228 L X 1000 mL/L = 228 mL

Explanation:

3 0
2 years ago
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