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Reil [10]
3 years ago
5

Can someone please help me with this, I’ll give Brainly!

Chemistry
1 answer:
Art [367]3 years ago
5 0

Answer:

Explanation:

See attached table.  

Note that:

1 mole = 6.02x10^23

Molar mass is grams/mole.  For the elements, the atomic mass is the same number as molar mass, just expressed as grams/mole.

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What is the value of the bond angles in sih4?
kirill115 [55]
<span>109.5°.
       
VESPR helps predict the bond angles with the electrons being the most out. By looking that the structure of the molecule, one Si and four H, the Si atom can be seen as the center and the four H atoms can be seen around it. Now think about how the H atoms would be placed, ideally they would be placed the farthest distance from each other equidistant. So in this case it would be 109.5°.</span>
7 0
4 years ago
Copper has two naturally occurring isotopes, 63Cu Gsotopic mass 629396 arnu) and 65Cu Osotopic mass 64.9278 amu). If copper has
madam [21]

<u>Answer:</u> The percentage abundance of _{29}^{63}\textrm{Cu} and _{29}^{65}\textrm{Cu} isotopes are 75.77% and 24.23% respectively

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i   .....(1)

Let the fractional abundance of _{29}^{63}\textrm{Cu} isotope be 'x'. So, fractional abundance of _{29}^{63}\textrm{Cu} isotope will be '1 - x'

  • <u>For _{29}^{63}\textrm{Cu} isotope:</u>

Mass of _{29}^{63}\textrm{Cu} isotope = 62.9396 amu

Fractional abundance of _{29}^{63}\textrm{Cu} isotope = x

  • <u>For _{29}^{65}\textrm{Cu} isotope:</u>

Mass of _{29}^{65}\textrm{Cu} isotope = 64.9278 amu

Fractional abundance of _{29}^{65}\textrm{Cu} isotope = 1 - x

  • Average atomic mass of copper = 63.546 amu

Putting values in equation 1, we get:

63.546=[(62.9396\times x)+(64.9278\times (1-x))]\\\\x=0.6950

Percentage abundance of _{29}^{63}\textrm{Cu} isotope = 0.6950\times 100=69.50\%

Percentage abundance of _{29}^{65}\textrm{Cu} isotope = (1-0.6950)=0.305\times 100=30.50\%

Hence, the percentage abundance of _{29}^{63}\textrm{Cu} and _{29}^{65}\textrm{Cu} isotopes are 69.50% and 30.50% respectively.

4 0
3 years ago
A Cobalt (Co) atom has a mass number of 60. Its atomic number is 27. How many neutrons does the cobalt atom have?
Roman55 [17]

Answer:

33 Neutrons

Explanation:

Atomic Mass = # of Protons + # of Neutrons

Atomic Number = Proton count

Atomic Mass of Co = 27 Protons + x Neutrons

60 = 27 + x

x = 33

6 0
4 years ago
Which element would you expect to have a higher electronegativity than nitrogen (N)?
Umnica [9.8K]
The answer is <span>Fluorine my dude

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6 0
4 years ago
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If you had 6 mol of oxygen and 12 mol of mercury, what would be the limiting reactant? show your work
gayaneshka [121]

The limiting reactant between the reaction of 6 moles of oxygen and 12 moles of mercury is mercury (Hg)

<h3>Balanced equation </h3>

4Hg + O₂ —> 2Hg₂O

From the balanced equation above,

4 moles of Hg reacted with 1 mole of O₂

<h3>How to determine the limiting reactant</h3>

From the balanced equation above,

4 moles of Hg reacted with 1 mole of O₂

Therefore,

12 moles of Hg will react with = 12 / 4 = 3 moles of O₂

From the above calculation, we can see that only 3 moles of O₂ out of 6 moles given is required to react completely with 12 moles of Hg.

Thus, Hg is the limiting reactant and O₂ is the excess reactant .

Learn more about stoichiometry:

brainly.com/question/14735801

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3 0
2 years ago
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