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Reil [10]
2 years ago
5

Can someone please help me with this, I’ll give Brainly!

Chemistry
1 answer:
Art [367]2 years ago
5 0

Answer:

Explanation:

See attached table.  

Note that:

1 mole = 6.02x10^23

Molar mass is grams/mole.  For the elements, the atomic mass is the same number as molar mass, just expressed as grams/mole.

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Why does the polyatomic anion OH need to gain
salantis [7]

Answer:Well-known examples are sodium hydroxide (NaOH) with OH- as the polyatomic anion, calcium carbonate (CaCO3), and ammonium nitrate (NH4NO3), which contains two polyatomic ions: NH+ and NO3-. ... The properties of compounds containing polyatomic ions are very similar to those of binary ionic compounds.

Explanation:

5 0
3 years ago
Given 6.98 x 10 4 power grams of iron, calculate the moles of iron present
KiRa [710]

Answer:

1249.88 mol.

Explanation:

∵ no. of moles of Fe = mass of Fe/atomic weight of Fe.

<em>∴ no. of moles of Fe </em>= (6.98 x 10⁴ g)/(55.845 g/mol) = <em>1249.88 mol.</em>

6 0
3 years ago
The Valence Electrons of an Atom of Which Element would feel a Greater Effective Nuclear Charge than the Valence?
kumpel [21]
The effective nuclear charge is an innate property of a specific element. It is the pull of force that an electron feels from the nucleus. It is related to the valence electron by the equation: Z* = Z-S, where Z* is the effective nuclear charge, Z is the atomic number and S is the shielding constant.

For the following elements in the choices, these are their values of Z*:

Aluminum - +12.591
Beryllium - +1.912
Hydrogen - +1
Carbon - +4

The effective nuclear charge of Boron is +3. Thus, the answers are  Aluminum and Carbon.
5 0
3 years ago
In terms of bonds, what would the molecule C₆H₁₂ be classified as?
Colt1911 [192]

Answer:

Alkene

Explanation:

5 0
3 years ago
Cho 4g CuO vào dung dịch axit clohidric 10% thì phản ứng vừa đủ.
Sholpan [36]

Answer:

Explanation:

a. CuO+ 2HCl⇒CuCl2+ H2O

b. n_{CuO}= \frac{4}{80}= 0,05 (mol)

⇒n_{CuCl2}= n_{CuO}=0,05 mol

⇒m_{CuCl2}= 0,05×135=6,75 (g)

c. n_{HCl}=2× n_{CuO}=0,1 (mol)

⇒m_{HCl}= 0,1×36,5= 3,65 (g)

⇒m_{dd HCl}= \frac{m_{HCl}}{10}×100=36,5 (g)

⇒ Nồng độ phần trăm dd sau phản ứng= Nồng độ % dd CuCl2=\frac{m_{CuCl2} }{m_{dd HCl+ m_{CuO} } }×100=\frac{6,75}{36,5+4} ×100≈ 16,67%

8 0
3 years ago
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