The volume of a sample of ammonia gas : 5.152 L
<h3>Further explanation</h3>
Given
0.23 moles of ammonia
Required
The volume of a sample
Solution
Assumed on STP
Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.
So for 0.23 moles :
= 0.23 x 22.4 L
= 5.152 L
Answer:
The law of the conservation of mass states that matter is neither created nor destroyed, only converted to other forms. Therefore, the mass never changes, even if its appearance does.
Explanation:
This is an aplication of Le Chatelier Principle. So, if you need further details about the theory behind the answer, search for this subject.
Here is the answer and the explanation.
You can realize that 1 mol of reactant produce 2 moles of products, which means that the trend of the reaction is to increase the volume (at constant pressure) or to increase the pressure (at constant volume). If you realease the pressure by increasing the volume, Le Chaelier principle permit you to predict a displacement of the equilibrium to the right (to the products). This is, because the equilibrium will try to restore (increase) the pressure by producing more molecules.
So, the answer is the option B. There will be a shift toward the products.
OILRIG:
Oxidation is loss (of electrons)
Reduction is gain (of electrons)
so...
The first one is an oxidation half-equation as the Sn loses electrons;
The second one is a reduction half-equation as the Cl₂ gains electrons
