Answer:
all soil are also different due to how they were form
1 is B (Just remember to have the same number of atoms on both sides)
2 is B (A precipitate is a solid forming from 2 liquids)
Answer:
Turning Sugar into Caramel
Explanation:
You turn sugar into caramel by burning sugar. Burning sugar is a chemical change.
Answer:
Explanation:
Law of conservation of mass:
According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.
This law was given by french chemist Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.
For example:
In given photosynthesis reaction:
6CO₂ + 6H₂O + energy → C₆H₁₂O₆ + 6O₂
there are six carbon atoms, eighteen oxygen atoms and twelve hydrogen atoms on the both side of equation so this reaction followed the law of conservation of mass.
Law of multiple proportion:
When two elements combine to form two or more compounds with different proportions, the weight of on element that combine with other elements in fixed proportion is in the ratio of small whole number.
For example:
Consider the example of carbon dioxide and carbon monoxide.
CO and CO₂
we are given with 1 g carbon on both case while 1.3 g oxygen for carbon monoxide and 2.6 for carbon dioxide. It means the ratio of oxygen is 1:2.
There is 1.3 g of oxygen in carbon monoxide for one g of carbon while in case of carbon dioxide there is 2.6 g of oxygen for one gram of carbon.
(Answer) 0.166 moles of copper (I) nitride are needed.
Mass of copper (I) oxide = 35.7 g
Moles of copper (I) oxide formed by the reaction = (Mass / molar mass)
= ( 35.7 g / 143.09 g/mol ) = 0.25 moles
According to the balanced chemical equation,
mole ratio of copper (I) nitride and copper (I) oxide = 2: 3
Therefore, moles of copper (I) nitride needed to form 0.25 moles of copper (I) oxide = (2/3 x 0.25) moles = 0.166 moles.
Thus, 0.166 moles of copper (I) nitride are needed to form 0.25 moles of copper (I) oxide.