The component with the most low atomic number that contains a total d-subshell in the ground state is copper. Copper's electron arrangement is [Ar]3d104s1 [ A r ] 3d 10 4 s 1 .
Further Explanation:
atomic number:
The nuclear number or proton number (image Z) of a synthetic component is the quantity of protons found in the core of a particle. It is indistinguishable from the charge number of the core. The nuclear number particularly distinguishes a compound component. In an uncharged iota, the nuclear number is likewise equivalent to the quantity of electrons.
The elemenents of the intermittent table arranged by atomic mass:
atomic Mass Name substance element Number
1.0079 Hydrogen 1
4.0026 Helium 2
6.941 Lithium 3
9.0122 Beryllium 4
atomic number speak to:
The nuclear number (otherwise called the proton number) is the quantity of protons found in the core of an iota. It is customarily spoken to by the image Z. The nuclear number exceptionally distinguishes a substance component. In a particle of impartial charge nuclear number is equivalent to the quantity of electrons.
Meaning of subshell:
A subshell is a subdivision of electron shells isolated by electron orbitals. Subshells are marked s, p, d, and f in an electron design.
Subject: chemistry
Level: High School
Keywords: atomic number, The elemenents of the intermittent table arranged by atomic mass, atomic number speak to, Meaning of subshell.
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Answer:
Chemical, cause physical are changes affecting the form of a chemical substance, but not its chemical composition. This doesn't affect the substance but the composition.
Explanation:
Answer:
5.0 x 10⁹ years.
Explanation:
- It is known that the decay of a radioactive isotope isotope obeys first order kinetics.
- Half-life time is the time needed for the reactants to be in its half concentration.
- If reactant has initial concentration [A₀], after half-life time its concentration will be ([A₀]/2).
- Also, it is clear that in first order decay the half-life time is independent of the initial concentration.
- The half-life of K-40 = 1.251 × 10⁹ years.
- For, first order reactions:
<em>k = ln(2)/(t1/2) = 0.693/(t1/2).</em>
Where, k is the rate constant of the reaction.
t1/2 is the half-life of the reaction.
∴ k =0.693/(t1/2) = 0.693/(1.251 × 10⁹ years) = 5.54 x 10⁻¹⁰ year⁻¹.
- Also, we have the integral law of first order reaction:
<em>kt = ln([A₀]/[A]),</em>
where, k is the rate constant of the reaction (k = 5.54 x 10⁻¹⁰ year⁻¹).
t is the time of the reaction (t = ??? year).
[A₀] is the initial concentration of (K-40) ([A₀] = 100%).
[A] is the remaining concentration of (K-40) ([A] = 6.25%).
∴ (5.54 x 10⁻¹⁰ year⁻¹)(t) = ln((100%)/( 6.25%))
∴ (5.54 x 10⁻¹⁰ year⁻¹)(t) = 2.77.
∴ t = 2.77/(5.54 x 10⁻¹⁰ year⁻¹) = 5.0 x 10⁹ years.
Answer:
B
Explanation:
Because it is viewed in a different place
