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nata0808 [166]
3 years ago
10

What are the minimum, first quartile, and maximum of the data set 55 54 59 61 61 62 68 70 72

Mathematics
1 answer:
Sonja [21]3 years ago
6 0
Minimum is 55 and I think the first quartile is 83.5 and the max is 72
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Find the sixth term in the following arithmetic sequence.<br> 1/4 , 1/8 ,0...
Shtirlitz [24]

Answer: 3/8

1/4 + 1/8 divided by 2

3 0
3 years ago
Identify the zeros of the function f(x) = 4x2 − 8x − 1 using the Quadratic Formula. HELP ASAP!!
forsale [732]

1+\dfrac{\sqrt{5}}{2},1-\dfrac{\sqrt{5}}{2}

Step-by-step explanation:

The given equation is 4x^{2}-8x-1

Let a be the coefficient of x^{2}

Let b be the coefficient of x

Let c be the constant.

Then the roots α,β for the equation ax^{2}+bx+c are \dfrac{-b+\sqrt{b^{2}-4ac} }{2a},\dfrac{-b-\sqrt{b^{2}-4ac} }{2a}

So,α=\frac{-b+\sqrt{b^{2}-4ac} }{2a}=\frac{8+\sqrt{64+16} }{8}=\frac{8+4\sqrt{5}}{8}=1+\frac{\sqrt{5}}{2}

β=\frac{-b-\sqrt{b^{2}-4ac} }{2a}=\frac{8-\sqrt{64+16} }{8}=\frac{8-4\sqrt{5}}{8}=1-\frac{\sqrt{5}}{2}.

So the roots are 1+\frac{\sqrt{5}}{2},1+\frac{\sqrt{5}}{2}

5 0
3 years ago
In 10 and 11, find the area in square units of each polygon.
alexandr1967 [171]

Answer:

10: 12 units^2 11: 33 units^2

Step-by-step explanation:

10:

Divide into square and 2 triangles (for simplicity)

square=9

one triangle=3/2

both triangles combined=3

9+3=12

11:

divide into 2 triangles

top triangle: height= 4, base=6

bottom triangle: height= 7, base=6

top=12

bottom=21

Add, 33.

7 0
2 years ago
Read 2 more answers
Find a equation of a line that is perpendicular to y=-4x+3 and passes through the point (4,-1).
Marina86 [1]

Given:

The given equation is:

y=-4x+3

A line is perpendicular to the given line and passes through the point (4,-1).

To find:

The equation of required line.

Solution:

The slope intercept form of a line is:

y=mx+b

Where, m is slope and b is y-intercept.

We have,

y=-4x+3

Here, the slope of the line is -4 and the y-intercept is 3.

Let the slope of required line be m.

We know that the product of slopes of two perpendicular lines is -1. So,

m\times (-4)=-1

m=\dfrac{-1}{-4}

m=\dfrac{1}{4}

The slope of required line is m=\dfrac{1}{4} and it passes through the point (4,-1). So, the equation of the line is:

y-(-1)=\dfrac{1}{4}(x-4)

y+1=\dfrac{1}{4}(x)-\dfrac{4}{4}

y=\dfrac{1}{4}x-1-1

y=\dfrac{1}{4}x-2

Therefore, the equation of the required line is y=\dfrac{1}{4}x-2.

5 0
3 years ago
Can i please get this answer ​ if i get it i can send maths sa1 question paper for 8 th class
vodka [1.7K]

Answer:

なた方やタハアはワタは真綿は他和定や6

Step-by-step explanation:

15-x2/3627

5 0
2 years ago
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