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nata0808 [166]
3 years ago
10

What are the minimum, first quartile, and maximum of the data set 55 54 59 61 61 62 68 70 72

Mathematics
1 answer:
Sonja [21]3 years ago
6 0
Minimum is 55 and I think the first quartile is 83.5 and the max is 72
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Please help me ASAP!!
vodomira [7]

It's A.



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4 0
4 years ago
If an ambulance has an average speed of 0.83 miles per minute and an average response time of 8 minutes, what is the average dis
Mrac [35]

Answer: The average distance the ambulance travels to reach an emergency situation is 6.64 miles.

Step-by-step explanation:

Hi, to answer this question we have to apply the speed formula:

Speed rate = distance / time  

Replacing with the values given:

0.83 miles per minute  = d / 8 minutes

Solving for d (distance)

0.83 mpm x 8 m =d

d =6.64 miles

The average distance the ambulance travels to reach an emergency situation is 6.64 miles.

Feel free to ask for more if needed or if you did not understand something.

4 0
3 years ago
What is the slope of a line parallel to line B?<br><br><br> -1/3<br><br> 2/5<br><br> 5/2<br><br> 5/3
Mice21 [21]
 2/5is the answer. Hope is helps
3 0
3 years ago
Coordinates (-3, 5), ( -3, 8), and (2, 5). The triangles was dilated by a scale favtor of 3. What is the area of the dilated tri
Otrada [13]

Answer:

The area of the triangle is 7.5 unit²

Step-by-step explanation:

Here we have the coordinates given as

(-3, 5) (-3, 8) and (2, 5)

Let us call the points A = (-3, 5)

B = (-3, 8) and

C = (2, 5)

Therefore the lengths of the sides of the triangle are

AB = a =  \sqrt{(-3-(-3))^2+(5-8)^2} =  3

AC = b = \sqrt{(-3-2)^2+(5-5)^2} =  5

BC = c = \sqrt{(-3-2)^2+(8-5)^2} =  \sqrt{34}

Therefore the Area can be derived from Heron's formula which is

A =  \sqrt{s\times (s-a)\times (s-b)\times (s-c)} where s = semi perimeter or (a + b + c)/2

Therefore, plugging the values, we get

s =   (3 + 5 + √34)/2 = 6.9155≈6.92

A =  \sqrt{6.92\times (6.92-3)\times (6.92-5)\times (6.92-\sqrt{34} )} = 7.499≈7.5.

7 0
4 years ago
Read 2 more answers
Liola drives 17km up a hill that is at a grade of 14 degrees. What horizontal distance, to the nearest tenth of kilometer, has s
nevsk [136]

Answer:

16.5km

Step-by-step explanation:

Liola drives 17km up a hill that is at a grade of 14 degrees. What horizontal distance, to the nearest tenth of kilometer, has she covered?

We solve using Trigonometric function of Cosine

cos theta = Adjacent/Hypotenuse

Theta = 14°

Hypotenuse = Distance up the hill = 17km

Adjacent = Horizontal distance = x

Hence,

cos 14 = x/17

Cross Multiply

x = cos 14 × 17

x = 16.495027347km

Approximately = 16.5km

The horizontal distance = 16.5km

4 0
3 years ago
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