9/27=33.3% repeating 3 = 0.3 repeating 3
18/27= 66.6 repeating 6 = 0.6 repeating 6
Answer:
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Get out of your own head. ...
Consider the time of the class. ...
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Reach out
Step-by-step explanation:
This requires the Poisson distribution, where
area = 5-acres
and mean number of field mice = 12 (in 5-acres of field)
therefore
lambda=12 (mean, given)
and the probability of k mice in the 5-acre field is given by the Poisson distribution as
P(X=k)=lambda^k * e^(-lambda) / k! ..............(1)
To find the probability of having LESS than 7 field mice, we add the probabilities of 0 to 6, which is
P(X<7)=P(X=0)+P(X=1)+...+P(X=6)
evaluating with equation (1) for X=0 to 6, we get:
0 0.0000061 0.0000742 0.0004423 0.0017704 0.0053095 0.0127416 0.025481Total = 0.045822
Answer: The probability that fewer than 7 field mice are found in the 5-acre field is 0.0458.
Answer:
cannot be factored
Step-by-step explanation:
The equation cannot be simplified so you have to use the quadratic formula
and you will get imaginary numbers from the formula
Answer:
The answer to your question is
x = -2 and y = 10 or x = 10 and y = -2
Step-by-step explanation:
x + y = 8 (1) from (1) x = 8 - y
xy = - 20 (2)
Solve them by substitution
(8 - y) y = - 20
8y - y² = -20
y² - 8y - 20 = 0
( y - 10) (y + 2) = 0
y - 10 = 0 and y + 2 = 0
<u> y1 = 10 </u> <u>y2 = -2</u>
x1 = 8 - 10 x2 = 8 - -2
<u>x1 = -2</u> <u> x2 = 10</u>