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Answer:
2.8 g KOH
Explanation:
We can find the amount of moles we need by multiplying 0.500 L and the molarity given, 0.10 M (molarity is moles of solute divided by liters of solution). The liters cancel out, leaving us with moles; we can then take the moles and convert it to grams of KOH by using the molar mass of KOH.
0.500 L x 0.10 mol/1 L x 56.106 g /1 mol = 2.8 g KOH (two significant figures)
Answer:
lol this is what you get for not answering my question and stealing points
Explanation:
Answer:
Refer to attached file below
Hope it helps..
Have a great day :P
Answer:
Explanation:
= Initial Concentration of KCl = 2.7 M
= Volume of KCl = 1 M
= Final concentration of KCl = 1 M
= Amount of water
We have the relation
The amount of water that is to be added is .