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elena55 [62]
2 years ago
15

8. Write the formulas for and give the names of

Chemistry
1 answer:
kobusy [5.1K]2 years ago
6 0
Answer is c...............
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Is science logical please help meeeeeee
atroni [7]

Answer:

It kind of is logical so my answer is yes

6 0
3 years ago
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A chemical reaction in which two or more substances undergo a chemical union to form a more complex substance is a _______ react
Georgia [21]
I believe the correct answer is B. Combination.
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3 years ago
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ammonia gas is used as refrigerant 0.474 atm. Pressure is required to change 2000 cm3 sample of ammonia initially at 1.0 atm to
Andreas93 [3]

Answer: The pressure required is 0.474 atm

Explanation:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}V}   (At constant temperature and number of moles)

The equation is,

{P_1V_1}={P_2V_2}

where,

P_1 = initial pressure of gas = 1.0 atm

P_2 = final pressure of gas = ?

V_1 = initial volume of gas = 2000cm^3

V_2 = final volume of gas = 4.22dm^3=4220cm^3    (1dm^3=1000cm^3)

Now put all the given values in the above equation, we get:

{1.0\times 2000}={P_2\times 4200}

P_2=0.474atm

The pressure required is 0.474 atm

5 0
2 years ago
If 50 ml of 0.235 M NaCl solution is diluted to 200.0 ml what is the concentration of the diluted solution
Helen [10]

This is a straightforward dilution calculation that can be done using the equation

M_1V_1=M_2V_2

where <em>M</em>₁ and <em>M</em>₂ are the initial and final (or undiluted and diluted) molar concentrations of the solution, respectively, and <em>V</em>₁ and <em>V</em>₂ are the initial and final (or undiluted and diluted) volumes of the solution, respectively.

Here, we have the initial concentration (<em>M</em>₁) and the initial (<em>V</em>₁) and final (<em>V</em>₂) volumes, and we want to find the final concentration (<em>M</em>₂), or the concentration of the solution after dilution. So, we can rearrange our equation to solve for <em>M</em>₂:

M_2=\frac{M_1V_1}{V_2}.

Substituting in our values, we get

\[M_2=\frac{\left ( 50 \text{ mL} \right )\left ( 0.235 \text{ M} \right )}{\left ( 200.0 \text{ mL} \right )}= 0.05875 \text{ M}\].

So the concentration of the diluted solution is 0.05875 M. You can round that value if necessary according to the appropriate number of sig figs. Note that we don't have to convert our volumes from mL to L since their conversion factors would cancel out anyway; what's important is the ratio of the volumes, which would be the same whether they're presented in milliliters or liters.

5 0
3 years ago
What changes chemical energy to something you can use
lutik1710 [3]

based on the law of conservation of energy its it atoms hold by strong chemical bonds

6 0
3 years ago
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