A. The balanced chemical equation is correct:
k2co3 + 2hcl --> 2kcl + co2 + h2o
B. First let us calculate the moles of K2CO3.
moles K2CO3 = 3 g / (138.205 g/mol) = 0.0217 mol
From the equation, we need 2 moles of HCl per 1 mole of
K2CO3, hence:
moles HCl needed = 0.0217 mol * 2 = 0.0434 mol
So the volume required is:
volume HCl = 0.0434 mol / 6 M = 7.24 x 10^-3 L = 7.24 mL
C. The number of moles of HCl and KCl is equal hence:
moles KCl = 0.0434 mol
The molar mass of KCl is 74.5513 g/mol, so the mass is:
mass KCl = 0.0434 mol * 74.5513 g/mol = 3.24 grams
1) during daylight, especially around noon, the relatively high air **temperature** and low humidity caused high evaporation, extracting pore water from the beach and leaving the **salt** behind, thereby resulting in high salinity near the beach surface (intertidal zone)
2) • algae and other intertidal plants grow in the abundant sunlight and support an entire food chain of animals
• constant wave action supplies the tide pool with **nutrients** and oxygen
• food is abundant
• a varied substrate provides hiding places and surfaces to cling to
3) the intertidal zone is one of a number of **marine** biomes or habitats, including: estuary (spray zone), neritic (lower/shallow zone), surface (middle zone), deep zones (high zones)
Answer:
Spectrum 1- Biphenyl
Spectrum 2 - Benzil
Spectrum 3 - Bibenzyl
Explanation:
<u>For Benzil:
</u>
<u>
</u>The Spectrum - 2 shows this compound.The C=O and C-H bond stretching observed at following values.
<u> For Biphenyl:
</u>
<u>
</u>Spectrum - 1 shows this compound.
There are stretching vibrations from 
due to C-H stretching and C-C stretching respectively of aromatic ring only.
<u>For Bibenzyl:
</u>
Spectrum - 3 shows this compound
There are stretching vibrations at 
due to C-H stretching and C-C stretching of aromatic ring.
Along with this, stretching vibrations at 
due to C-H of alkyl.
Answer:
63.55 amu
Explanation:
(0.692 * 62.930) + (0.308 * 64.928) = 63.55 amu
Copper has two naturally occurring
isotopes: copper-63 (69.17%) and
copper-65 (30.83%).
Calculate the average atomic mass of
copper if the relative masses of the
isotope are copper 63 (62.93 amu)
and copper-65 (64.93 amu).
Cu-63 (0.6917 x 62.93 amu)
Cu-65 + (0.3083 x 64.93 amu)
Avg. mass = 63.55 amu
