Answer:
Mole fraction = 0,0166
Explanation:
Mole fraction is defined as mole of a compound per total moles of the mixture. In the solution, the solute is fructose and the solvent is water. That means you need to find moles of fructose and moles of water.
The molecular mass of fructose is 180,16g/mol and mass of water is 18,02 g/mol. Using these values:
91,7g fructose × (1mol / 180,16g) = <em>0,509 moles of fructose</em>
545g water × (1mol / 18,02g) = <em>30,24 moles of water</em>
Thus, mole fraction of fructose is:
<em>Mole fraction = 0,0166</em>
I hope it helps!
I can’t see the question :/
Remember:
6.022×10²³ molecules = 1 mol (Avogadro's number)
NH₃ = ammonia
To get molar mass of NH₃, add the mass of nitrogen + 3 times the mass of hydrogen (because there are 3 hydrogens in NH₃).
14.01 + 3(1.01) = 17.04 grams NH₃ = molar mass
1) Set up your equation. You want to cancel out molecules, and get to grams through moles.
So multiply 3.4×10²⁴ molecules of ammonia × 1 mol of ammonia × 17.04 grams of ammonia and divide it by 6.022×10²³ molecules of ammonia and 1 mol of ammonia.
3.4×10²⁴ molecules of ammonia × 1 mol of ammonia × 17.04 grams of ammonia
6.022×10²³ molecules of ammonia 1 mol of ammonia
Your answer should come out to be: 96.20724 grams of ammonia
Round to 2 sig figs: 96 grams of ammonia
Answer:
a. Ag+ and Ca2+
The pair of cations related to the question are as below:
a. Ag+ and Ca2+
b. Hg2^2+ and Ag^+
c. Ba^2+ and Na^+
d. Ca^2+ and Ba^2+
e. Pb^2+ and Ag^+
Explanation:
a. Ag+ and Ca2+ correct
Ag+ will precipitate with dilute hydrobromic acid (HBr) but Ca+2 will not
Ag+ + Br- -----------------> AgBr (s)
Ca+2 + 2Br- ---------------> CaBr2 (aq)
B) Hg2^2+ and Ag^+ Incorrect
Both Hg2^2+ and Ag^+ will precipitate. One has to precipitate while the other does not, so this is incorrect.
C) Ba2 and Na+ both won't precipitate. Incorrect
One has to precipitate while the other does not, so this is incorrect.
D) Ca2+ and Ba 2+both won't precipitate. Incorrect
One has to precipitate while the other does not, so this is incorrect.
E ) Both Pb2 and Ag+ will precipitate. Incorrect
One has to precipitate while the other does not, so this is incorrect.