Why is the ionic compound NaCl (table salt) able to dissolve in a glass of the molecular compound water (H2O)?

Chemistry

2 answers:

Lesechka [4]3 years ago

5 0

I believe that it is C.

coldgirl [10]3 years ago

3 0

<h3><u>Answer;</u></h3>

Ions from the solute have a strong attraction to the polar solvent

<h3><u>Explanation;</u></h3>

<em><u>When sodium is added to water, the sodium ions Na+ are attracted to the oxygen side of the water molecules, while chloride ions Cl- are attracted to the positively charged hydrogen side of water molecule.</u></em>

This causes sodium ion to split in water and dissolve into separate sodium ions and chloride ions.

The process can be represented by this equation.

NaCl(s) --> Na+(aq) + Cl-(aq)

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MrMuchimi

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How many grams of sulfuric acid is needed to neutralize 380 ml of solution with pH = 8.94

erma4kov [3.2K]

Answer : The mass of sulfuric acid needed is $16.23\times 10^{-5}g$ .

Solution : Given,

pH = 8.94

Volume of solution = 380 ml = $380\times 10^{-3}$ $(1ml=10^{-3}L)$

Molar mass of sulfuric acid = 98.079 g/mole

As we know,

$pH+pOH=14\\pOH=14-8.94=5.06$

$pOH=-log[OH^-]$

$5.06=-log[OH^-]$

$[OH^-]=0.00000871=8.71\times 10^{-6}mole/L$

Now we have to calculate the moles of $OH^-$ .

Formula used : $Moles=Concentration\times Volume$

$\text{ Moles of }[OH^-]=\text{ Concentration of }[OH^-]\times Volume\\\text{ Moles of }[OH^-]=(8.71\times 10^{-6}mole/L)\times (380\times 10^{-3}L)=3309.8\times 10^{-9}moles$