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Natalija [7]
3 years ago
7

The length of a rectangle is 6m longer than its width. If the perimeter of the rectangle is 52m, find its area

Mathematics
1 answer:
sveticcg [70]3 years ago
4 0
If length is x, then width is 6+x 
<span>Perimeter = 2*(x + 6+x) = 52 </span>
<span>2*6 + 2*2x = 52 </span>
<span>4x = 52 - 12 = 40 </span>
<span>x = 40/4 = 10 </span>

<span>Area = length*width = 10*(6+10) </span>
<span>Area = 10*16 = 160 meter square</span>
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Is x=12 a solution to the given inequality x &gt; 5
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Answer: True

Step-by-step explanation:

Substitute 12 for x in the inequality

x > 5

12 > 5

12 is greater than 5 so x = 12 is a solution to x > 5

4 0
2 years ago
PLEASE I NEED HELP WITH THIS
Ber [7]

Given:

The figure of a circle.

To find:

The measure of arc AD and measure of each arc.

Solution:

The measure of arc is equal to the central angle of that arc.

The central angle of arc AD is 105 degrees. So,

m(arc(AD))=105^\circ

The central angle of arc BC is 35 degrees. So,

m(arc(BC))=35^\circ

The central angle of arc CD is 50 degrees. So,

m(arc(CD))=50^\circ

The central angle of a complete circle is 360 degrees. So,

m(arc(AD))+m(arc(BC))+m(arc(CD))+m(arc(AB))=360^\circ

105^\circ+35^\circ+50^\circ+m(arc(AB))=360^\circ

190^\circ+m(arc(AB))=360^\circ

m(arc(AB))=360^\circ-190^\circ

m(arc(AB))=170^\circ

Therefore, the measure of arc AD is 105°, the measure of arc BC is 35°, the measure of arc CD is 50° and the measure of arc AB is 170°

3 0
3 years ago
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Lemur [1.5K]

In both cases,

AB^2=AD^2

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16x^4-144x^3+244x^2+360x+100=x^4+2x^3+9x^2+8x+16

15x^4-146x^3+235x^2+352x+84=0

(x-7)(3x+2)(5x^2-17x-6)=0\implies\boxed{x=-\dfrac23\text{ or }x=7}

(again, omit the solutions that would give a negative length for either AB or AD)

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