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3 years ago

Energy can be changed from one form to another. Which terms can be used to describe these changes? Check all that apply.

Physics

2 answers:

OverLord2011 [107]3 years ago

6 0

Answer:

A.) Energy Conversion

D.) Energy Transformation

[ Correct on Edgenuity ]

Explanation:

These other listed options are incorrect because :

(bolded sentences are the reason why)

Incorrect : B.) Energy conservation

Energy conservation is the prevention of the wasteful use of energy, especially in order to ensure its continuing availability. This does not describe change; it talks about prevention.

Incorrect : C.) Energy correlation

The energy correlation is a measure of how much the movement of one electron is influenced by the presence of all other electrons. This only describes the measure of movement and not the physical form of energy change.

Incorrect : E.) Energy transference

Energy transference is the conversion of one form of energy into another, or the movement of energy from one place to another. It has the correct definition but this is the incorrect term that's being used. Instead, you would have used energy transformation.

*[ A and B are correct, I recieved 100% on the quiz on Edgenuity ]*

Hope this helped! Have a wonderful day! :)

Dominik [7]3 years ago

4 0

Answer:

A Energy Conversion

B Energy Conservation

D Energy Transformation

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A 124-kg balloon carrying a 22-kg basket is descending with a constant downward velocity of 20.0 m/ s. A I.O-kg stone is thrown

nadya68 [22]

(a) 296.6 m

The motion of the stone is the motion of a projectile, thrown with a horizontal speed of

$v_x = 15.0 m/s$

and with an initial vertical velocity of

$v_{y0} = -20.0 m/s$

where we have put a negative sign to indicate that the direction is downward.

The vertical position of the stone at time t is given by

$y(t) = h + v_{0y} t + \frac{1}{2}gt^2$ (1)

where

h is the initial height

g = -9.81 m/s^2 is the acceleration due to gravity

The stone hits the ground after a time t = 6.00 s, so at this time the vertical position is zero:

y(6.00 s) = 0

Substituting into eq.(1), we can solve to find the initial height of the stone, h:

$0 = h + v_{0y} y + \frac{1}{2}gt^2\\h = -v_{0y} y - \frac{1}{2}gt^2=-(-20.0 m/s)(6.00 s) - \frac{1}{2}(9.81 m/s^2)(6.00 s)^2=296.6 m$

(b) 176.6 m

The balloon is moving downward with a constant vertical speed of

$v_y = -20 m/s$

So the vertical position of the balloon after a time t is

$y(t) = h + v_y t$

and substituting t = 6.0 s and h = 296.6 m, we find the height of the balloon when the rock hits the ground:

$y(t) = 296.6 m + (-20.0 m)(6.00 s)=176.6 m$

(c) 198.2 m

In order to find how far is the rock from the balloon when it hits the ground, we need to find the horizontal distance covered by the rock during the time of the fall.

The horizontal speed of the rock is

$v_x = 15.0 m/s$

So the horizontal distance travelled in t = 6.00 s is

$d_x = v_x t = (15.0 m/s)(6.00 s)=90 m$