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o-na [289]
2 years ago
6

Undersea mountain ranges in the middle of the ocean floors are known as d͟e͟e͟p͟-͟o͟c͟e͟a͟n͟ ͟t͟r͟e͟n͟c͟h͟e͟s.

Physics
2 answers:
REY [17]2 years ago
7 0

False

mid-ocean ridge

NikAS [45]2 years ago
3 0

Answer : False

Undersea mountain ranges in the middle of the ocean floors are known as <u>Mid-Ocean Ridge</u>

Mountain range located on the sea floor in the middle of the ocean.

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which principles of training refers o placing increased demands on the body? A. Specificity B. cross-training c.type D.overload
Anuta_ua [19.1K]
Overload <<<<<<<<<<<<<<<<<<<<<<<<<<<<<,,,,,,,,
5 0
2 years ago
20 points and brainliest‼️‼️‼️‼️
Anastasy [175]

Answer:

0 N

Explanation:

Applying,

F = qvBsin∅................. Equation 1

Where F = Force on the charge, q = charge, v = Velocity, B = magnetic charge, ∅ = angle between the velocity and the magnetic field.

From the question,

Given: q = 4.88×10⁻⁶ C, v = 265 m/s, B = 0.0579 T, ∅ = 0°

Substitute these values into equation 1

F = ( 4.88×10⁻⁶)(265)(0.0579)(sin0)

Since sin0° = 0,

Therefore,

F = 0 N

3 0
3 years ago
12
Harrizon [31]

Answer:

B. 6

Explanation:

i think... im in 7th grade and haven't really leaned this but im like 60% sure but i migjt be wrong

7 0
2 years ago
Read 2 more answers
Lisa is conducting an investigation to determine the coefficient of friction between two surfaces. She uses a 25 kg block. What
Paladinen [302]

Answer:

245.25

Explanation:

1 kg is 9.81 newtons

4 0
3 years ago
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A horse is pulling 53.0 kg plow forward while the ground exerts a 275 N force, and the plow accelerates at 0.222 m/s^2. what is
JulsSmile [24]
Answer:
Magnitude of force the ground exerts on the plow = 263.234 N

Explanation:
Magnitude of force the ground exerts on the plow = Fground - Fplow
We are given that:
Fgound = 275 N
We will now calculate Fplow as follows:
Fplow = mass of horse * acceleration of plow
Fplow = 53 * 0.222
Fplow = 11.766 N

Now, substitute in the above equation to get magnitude of force the ground exerts on the plow as follows:
Magnitude of force the ground exerts on the plow = Fground - Fplow
Magnitude of force the ground exerts on the plow = 275 - 11.766
Magnitude of force the ground exerts on the plow = 263.234 N

Hope this helps :)
3 0
3 years ago
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