Answer:
F = 1958.4 N
Explanation:
By volume conservation of the fluid on both sides we can say that volume of fluid displaced on the side of the car must be equal to the volume of fluid on the other side
so we have



so the car will lift upwards by distance 1.2 m and the other side will go down by distance 15.55 m
So here the net pressure on the smaller area is given as

excess pressure exerted on the smaller area is given as


now the force required on the other side is given as



The current that would pass through the 30 ohms resistor is 2 A.
<h3>What is electric current?</h3>
Electric current is the rate of flow of electric charge round a conductor.
To calculate the electric current that would pass through the 30 ohms resistor, we use the formula below
Formula:
- I = V/Rt........... Equation 1
Where:
- I = Electric current passing through the 30 ohms resistor
- V = Voltage
- Rt = Total or effective resistance of the resistors.
From the question,
Given:
- V = 100 volts
- Rt = (30+20) ohms (since both resistors are connected in series)
Substitute these values into equation 1
Hence, The current that would pass through the 30 ohms resistor is 2 A.
Learn more about electric current here: brainly.com/question/1100341
Answer:
the answer is equal to 2.00v
Answer:
5.5 km
Explanation:
First, we convert the distance from km/h to m/s
910 * 1000/3600
= 252.78 m/s
Now, we use the formula v²/r = gtanθ to get our needed radius
making r the subject of the formula, we have
r = v²/gtanθ, where
r = radius of curvature needed
g = acceleration due to gravity
θ = angle of banking
r = 252.78² / (9.8 * tan 50)
r = 63897.73 / (9.8 * 1.19)
r = 63897.73 / 11.662
r = 5479 m or 5.5 km
Thus, we conclude that the minimum curvature radius needed for the turn is 5.5 km