Ask question

Ask question

All categories

musickatia [10]

3 years ago

6

Which bright object is in shadow

1 answer:

IRINA_888 [86]3 years ago

5 0

My best guess would be sun because it is bright but is surrounded by shadows on all sides.

You might be interested in

I know the answer but what type of energy is this.

k0ka [10]

Answer:

Elastic potential energy

Explanation:

7 0

3 years ago

Read 2 more answers

How would you describe the magnetic field produced by a current in a straight wire?

Elena L [17]

The answer to this is C. The reason being is because if you were to use a compass then it would be making circular motions towards the middle of the wire.

4 0

4 years ago

Read 2 more answers

What is de Broglie's hypothesis ? Make sure to be specific (qualitative and quantitative)

victus00 [196]

Answer and Explanation:

DE BROGLIE 'S HYPOTHESIS :

According to De broglie the matter have dual nature it can behave as particle as well as wave
According to this hypothesis all matter have wave like property and having wavelength.
The de broglie wavelength is given by $\lambda =\frac{h}{P}$ here h is plank's constant and P is momentum
This hypothesis determines the probability of finding the object at a give point

3 0

3 years ago

A 282 kg bumper car moving right at 3.50 m/s collides with a 155 kg bumper car moving 1.8 m/s left. Afterwards, the 282 kg car m

Leto [7]

Answer: momentum afterwards = 1040.4kgm/s

Explanation:

8 0

3 years ago

An unstable particle at rest spontaneously breaks into two fragments of unequal mass. The mass of the first fragment is 3.00 10-

kirill [66]

Answer:0.478 c

Explanation:

Given

mass of lighter Particle $(m_1)=3\times 10^{-28} kg$

mass of heavier Particle $(m_2)=1.51\times 10^{-27} kg$

speed of lighter particle $(v_1)=0.834 c$

Let speed of heavier particle $=v_2$

and Momentum of the particle is given by

$P=\frac{mv}{\sqrt{1-(\frac{v}{c})^2}}$

$P_1=\frac{m_1v_1}{\sqrt{1-(\frac{v_1}{c})^2}}$

$P_1=\frac{3\times 10^{-28}\times 0.834 c}{\sqrt{1-(\frac{0.834 c}{c})^2}}$

$P_1=8.219\times 10^{-28} kg c$

$P_2=\frac{m_2v_2}{\sqrt{1-(\frac{v_2}{c})^2}}$

as momentum is conserved therefore $P_1=P_2$

$8.219\times 10^{-28} kg c=\frac{1.51\times 10^{-27}\times v_2}{\sqrt{1-(\frac{v_2}{c})^2}}$

$v_2=0.478 c$

3 0

3 years ago